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Hoochie [10]
3 years ago
6

Can someone help me out with this one?​

Mathematics
1 answer:
kakasveta [241]3 years ago
5 0

Answer:

F(x)=\left \{ {{-\frac{1}{2}+1, x

Step-by-step explanation:

There are 2 linear equations, one with an open circle and one with a closed one. Depending on where the circle is, that will tell you your start. Both circles start at 0 on the graph. The open circle means that the first equation will be   x < 0. The second equation has a closed circle so it will be x\geq 0 because the linear equation is increasing positively.

Now you need to the start point of both equations.

x   start point is 1 on the y-axis

x\geq 0   start point is 2 on the y-axis

Now you have to find the slope for the two equations

x  the equation goes up 1 and and over 2

x\geq 0  the equation goes up 2 and over 1

Now put together the equations

x \frac{-1}{2} + 1

x\geq 0  2x - 2

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nlexa [21]

Answer:

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Step-by-step explanation:

divide the first one by the second that might help

5 0
3 years ago
Simplify <br> (3xˆ5-2)ˆ1/2
ladessa [460]

All you need to do with this problem is convert (3x^5-2)^\frac{1}{2} into a square root. Then you'll get the answer \sqrt{3x^5-2}.

3 0
3 years ago
9. How many kilograms are in 14,500 grams?
serg [7]

Answer:

17

Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
A statue is mounted on top of a 21 foot hill. From the base of the hill to where you are standing is 57feet and the statue subte
AleksandrR [38]

Please find the attached diagram for a better understanding of the question.

As we can see from the diagram,

RQ = 21 feet = height of the hill

PQ = 57 feet = Distance between you and the base of the hill

SR= h=height of the statue

\angle SPR=Angle subtended by the statue to where you are standing.

\angle x=\angle RPQ= which is unknown.

Let us begin solving now. The first step is to find the angle \angle x which can be found by using the following trigonometric ratio in \Delta PQR :

tan(x)=\frac{RQ}{PQ} =\frac{21}{57}

Which gives \angle x to be:

\angle x=tan^{-1}(\frac{21}{57})\approx20.22^{0}

Now, we know that\angle x and \angle SPR can be added to give us the complete angle \angle SPQ in the right triangle \Delta SPQ.

We can again use the tan trigonometric ratio in \Delta SPQ to solve for the height of the statue, h.

This can be done as:

tan(\angle SPQ)=\frac{SQ}{PQ}

tan(7.1^0+20.22^0)=\frac{SR+RQ}{PQ}

tan(27.32^0)=\frac{h+21}{57}

\therefore h+21=57tan(27.32^0)

h\approx8.45 ft

Thus, the height of the statue is approximately, 8.45 feet.

3 0
3 years ago
Jerry purchased three pens for $1.19 each and six notebooks for $2.29 each. How many did Jerry spend altogether?
Masteriza [31]

Hi!

We will find the sum you are looking for like this:

3 * 1,19$ + 6 * 2,29$ = 3,57$ + 13,74$ = 17,31$.

Hope this helps!

6 0
4 years ago
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