Answer: 1, 2, 4, or 5
Step-by-step explanation:
The relationship in #3 is a function because all the x values are distinct, that is, none are repeated. (Y values don't matter.)
A function will not repeat any x values so if your goal is for the relationship in #4 to NOT be a function, repeat one of the x values. Any one will work.
Solution
4m - 2 < 2 or 6m + 2 ≥ 6
Step 1: Isolate the variable constant.
4m < 2 + 2 or 6m ≥ 6 - 2
Step 2: Simplify it.
4m <4 or 6m ≥4
Step 3: Solve for "m"
m < 4/4 or m ≥ 4/6
m < 1 or m ≥2/3
That is the solution.
Note: I have attached the graph. Please take a look at it.
Thank you :)
Answer:
(1.5, 3)
Step-by-step explanation:
Given the 2 equations
2x + 3y = 12 → (1)
y = x + 1.5 → (2)
Substitute y = x + 1. 5 into (1)
2x + 3(x + 1.5) = 12 ← distribute and simplify left side
2x + 3x + 4.5 = 12
5x + 4.5 = 12 ( subtract 4.5 from both sides )
5x = 7.5 ( divide both sides by 5 )
x = 1.5
Substitute x = 1.5 into (2) for corresponding value of y
y = 1.5 + 1.5 = 3
Solution is (1.5, 3)
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