(-2,6) iissssssss the answer
If A and B are equal:
Matrix A must be a diagonal matrix: FALSE.
We only know that A and B are equal, so they can both be non-diagonal matrices. Here's a counterexample:
![A=B=\left[\begin{array}{cc}1&2\\4&5\\7&8\end{array}\right]](https://tex.z-dn.net/?f=A%3DB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%262%5C%5C4%265%5C%5C7%268%5Cend%7Barray%7D%5Cright%5D)
Both matrices must be square: FALSE.
We only know that A and B are equal, so they can both be non-square matrices. The previous counterexample still works
Both matrices must be the same size: TRUE
If A and B are equal, they are literally the same matrix. So, in particular, they also share the size.
For any value of i, j; aij = bij: TRUE
Assuming that there was a small typo in the question, this is also true: two matrices are equal if the correspondent entries are the same.
Answer:
The correct answer is C
Step-by-step explanation:
82
The sum of the three angles is 180. One is given and the other we can figure out because it forms a straight line (180) with the angle to the left outside. The outside angle is 117, so 180-117 is 63.
So then add up the 3 angles in the triangle
63+35+y=180
y= 82
Answer: 3,168
Step-by-step explanation: If You Multiply The Original Cost Of The Textbook By 33 You Will Get A Product Of 3,186