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11Alexandr11 [23.1K]
3 years ago
11

Pleaseee help with math 6th

Mathematics
1 answer:
mel-nik [20]3 years ago
5 0
Shouldn’t it be a hexagon
four bases plus two bases is 6 bases
and a hexagon has six sides
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Verify that [tan(theta) + cot(theta)]^2 = sec^2(theta) + csc^2(theta)
Wittaler [7]

(tanθ + cotθ)² = sec²θ + csc²θ

<u>Expand left side</u>: tan²θ + 2tanθcotθ + cot²θ

<u>Evaluate middle term</u>: 2tanθcotθ = 2*\frac{sin\theta}{cos\theta}*\frac{cos\theta}{sin\theta} = 2

⇒ tan²θ + 2+ cot²θ

= tan²θ + 1 + 1 + cot²θ

<u>Apply trig identity:</u>  tan²θ + 1 = sec²θ

⇒ sec²θ + 1 + cot²θ

<u>Apply trig identity:</u>  1 + cot²θ = csc²θ

⇒ sec²θ + csc²θ

Left side equals Right side so equation is verified


7 0
2 years ago
Which of the following is an equation of the line that passes through the point (2, 2) and is parallel to the graph of the equat
pickupchik [31]

Answer:

B

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 3x - 1 ← is in slope- intercept form

with slope m = 3

Parallel lines have equal slopes, thus

y = 3x + c ← is the partial equation of the parallel line

To find c substitute (2, 2) into the partial equation

2 = 6 + c ⇒ c = 2 - 6 = - 4

y = 3x - 4 → B

4 0
3 years ago
Read 2 more answers
Subtract (6x² + 8x - 5) from (7x? + 8x - 4)
vampirchik [111]

Answer:

−6x^2+7x+1

Step-by-step explanation:

1)(7x+8x-4)=15x−4

2)15x-4-(6x^2+8x-5)=−6x2+7x+1

8 0
2 years ago
What is the slope of a line that is perpendicular to the line y = 1?
ValentinkaMS [17]
Y = 1
Using y = mx + c.
Compare to y = 1,    y = 0x + 1 ,
We can see that the slope m = 0 and the vertical intercept, c = 1.
For the line perpendicular to  y = 1
Condition for perpendicularity  m₁m₂ = -1
m₁ = 0,  m₂ = ?
0*m₂ = -1
m₂ = -1/0 = Negative Infinite or Infinite 
Slope of line perpendicular to y = 1, is  = Infinite. 
3 0
3 years ago
Read 2 more answers
Is it necessary to have a common denominator when you multiply two fractions? Explain.
Softa [21]

It is not necessary to have a common denominator when you multiply two fractions

<h3>How to determine the true statement?</h3>

The statement is about the relationship between the denominator of fractions when they are multiplied

Take for instance, we have the following fractions

a/b and x/y

In the above fractions, we have

Numerator = a and x

Denominator = b and y

Where b and y do not have the same value

When they are multiplied, we have

Product  = ax/by

The denominators do not have the same value

And we were able to calculate the product

This means that the fraction denominator do not have to be common

Read more about fractions at

brainly.com/question/1622425

#SPJ1

7 0
1 year ago
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