The domain of this function is x = all real numbers.
The range of this function is that y ≥ 0.
To find the domain, you need to look for exclusions. The only numbers that you exclude are when you can't divide by 0 or have a negative square root. Since this problem has no square root symbol or fractions, it is all real numbers.
For the range, we need to find the smallest value of y. y can get no smaller in this problem than when x = 0. In that case y also = 0. Because the lead coefficient is positive (4), we know that the graph is increasing. Therefore, we know that y must always be bigger than 0.
Answer:
Step-by-step explanation:
= 
= 
= 
= 15,625
Multiply $860 by .11 (11%) to find the answer.
$94.60 Is the interest earned.
Answer:
- The probability that overbooking occurs means that all 8 non-regular customers arrived for the flight. Each of them has a 56% probability of arriving and they arrive independently so we get that
P(8 arrive) = (0.56)^8 = 0.00967
- Let's do part c before part b. For this, we want an exact booking, which means that exactly 7 of the 8 non-regular customers arrive for the flight. Suppose we align these 8 people in a row. Take the scenario that the 1st person didn't arrive and the remaining 7 did. That odds of that happening would be (1-.56)*(.56)^7.
Now take the scenario that the second person didn't arrive and the remaining 7 did. The odds would be
(0.56)(1-0.56)(0.56)^6 = (1-.56)*(.56)^7. You can run through every scenario that way and see that each time the odds are the same. There are a total of 8 different scenarios since we can choose 1 person (the non-arriver) from 8 people in eight different ways (combination).
So the overall probability of an exact booking would be [(1-.56)*(.56)^7] * 8 = 0.06079
- The probability that the flight has one or more empty seats is the same as the probability that the flight is NOT exactly booked NOR is it overbooked. Formally,
P(at least 1 empty seat) = 1 - P(-1 or 0 empty seats)
= 1 - P(overbooked) - P(exactly booked)
= 1 - 0.00967 - 0.06079
= 0.9295.
Note that, the chance of being both overbooked and exactly booked is zero, so we don't have to worry about that.
Hope that helps!
Have a great day :P
