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4 years ago

Please I need help 20 POINTS!

Mathematics

1 answer:

lana [24]4 years ago

5 0

Mia made 18 cookies to share with her best friend at school. Each day she brought 2 cookies to share with her friend. How many days does she have to bring cookies to school?

Answer: 9

Solving Steps:

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A garden is in the shape of a square with a perimeter of

ElenaW [278]

The perimeter of a square is the sum of its sides and they are all equal, so to obtain the length of each of them we divide the perimeter of the first fence between 4:

P1= 64 feet/4 sides

P1= 16 feet

Then, the length of each side of the second fence will increase 2 feet at each end, as shown in the figure. We have then that the perimeter of the second fence is:

P2 = 20 feet x 4 sides

P2 = 80 feet

The sum of the perimeters of both fences is:

PT = P1 + P2

PT = 64 feet + 80 feet

PT = 144 feet

Total cost = 1.17 $ x 144 feet

Total cost = 168.48 $

The total cost of the fences was $ 168.48

6 0

3 years ago

what is the width of a rectangular prism when the surface area is 904 square feet, and it has a height of 10 feet and a length o

k0ka [10]

Answer:

The answer

Step-by-step explanation:

the width of a rectangular prism which has a height of 10 feet and a length of 14 feet should be 140 square feet

7 0

3 years ago

Addie bought lunch to go from a sandwich shop. She spent $12.00 for a $10.00 meal. What percent was the tip?

horsena [70]

Answer:

She gave a $2.00 tip witch would be %20 of her meal cost.

Step-by-step explanation:

</3 PureBeauty

4 0

3 years ago

Read 2 more answers

n parallelogram LMNO, MP = 21 m, LP = (y + 3) m, NP = (3y – 1) m, and OP = (2x – 1) m. What are the values of x and y? x = 10, y

seropon [69]

Answer:

The value of x = 11 and y = 2

Step-by-step explanation:

Given : parallelogram LMNO, MP = 21 m, LP = (y + 3) m, NP = (3y – 1) m, and OP = (2x – 1) m.

We have to find values of x and y.

Let P be the point of intersection of diagonals OM and LN.

In a parallelogram diagonal bisects at right angles and point of intersection divide diagonal in equal parts.

Thus, OP = MP and LP = PN

OP = MP , substitute the values, we get,

(2x-1) = 21

⇒ 2x = 22

⇒ x = 11

LP = PN , substitute the values, we get,

y + 3 = 3y -1

⇒ 3y - y = 4

⇒ 2y = 4

⇒ y = 2

Thus, the value of x = 11 and y = 2

8 0

4 years ago

A survey collected data on annual credit card charges in seven different categories of expenditures: transportation, groceries,

Andru [333]

Answer:

A. Null and alternative hypothesis:

$H_0: \mu_d=0\\\\H_a:\mu_d\neq 0$

B. Yes. At a significance level of 0.05, there is enough evidence to support the claim that there is signficant difference between the population mean credit card charges for groceries and the population mean credit card charges for dining out.

P-value = 0.00002

C. As the difference is calculated as (population 1 − population 2), being population 1: groceries and population 2: dinning out, and knowing there is evidence that the true mean difference is positive, we can say that the groceries annual credit card charge is higher than dinning out annual credit card charge.

The point estimate is the sample mean difference d=$840.

The 95% confidence interval for the mean difference between the population means is (490, 1190).

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that there is signficant difference between the population mean credit card charges for groceries and the population mean credit card charges for dining out.

Then, the null and alternative hypothesis are:

$H_0: \mu_d=0\\\\H_a:\mu_d\neq 0$

The significance level is 0.05.

The sample has a size n=42.

The sample mean is M=840.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=1123.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{1123}{\sqrt{42}}=173.2827$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{840-0}{173.2827}=\dfrac{840}{173.2827}=4.848$

The degrees of freedom for this sample size are:

$df=n-1=42-1=41$

This test is a two-tailed test, with 41 degrees of freedom and t=4.848, so the P-value for this test is calculated as (using a t-table):

$\text{P-value}=2\cdot P(t>4.848)=0.00002$

As the P-value (0.00002) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

At a significance level of 0.05, there is enough evidence to support the claim that there is signficant difference between the population mean credit card charges for groceries and the population mean credit card charges for dining out.

We have to calculate a 95% confidence interval for the mean difference.

The t-value for a 95% confidence interval and 41 degrees of freedom is t=2.02.

The margin of error (MOE) can be calculated as:

$MOE=t\cdot s_M=2.02 \cdot 173.283=350$

Then, the lower and upper bounds of the confidence interval are:

$LL=M-t \cdot s_M = 840-350=490\\\\UL=M+t \cdot s_M = 840+350=1190$

The 95% confidence interval for the mean difference is (490, 1190).

7 0

3 years ago