The number of people who bought £4 tickets are 139.
<h3>How to illustrate the equation?</h3>
Let £4 tickets be x
Let £5 tickets be y.
Therefore based on the information given, this will be:
x + y = 223 ..... i
4x + 5y = 936 ..... ii
From equation i
x = 213 - y
Put this into equation ii
4x + 5y = 936
4(213 - y) + 5y = 936
852 - 4y + 5y = 936
Collect like terms
y = 84
This implies that the number of £5 tickets is 84.
Recall that x + y = 223
x + 84 = 223
x = 223 - 84
x = 139
The number of £4 tickets is 139
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Answer:
123
Step-by-step explanation:
if the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadthif the perimeter of a rectrangular field of length 25 m is 86 m find its breadth
Answer:
(A) 49
Explanation:
Most of the equation is just explaining what length and width is.
Area = L (length) · W (Width)
Option One:
Length: 9
Width: 5
9 · 5 = 45
There is no option for 45 so we need to check option two.
Option Two:
Length: 7
Width: 7
7 · 7 = 49
There is an option for 49, so that is our answer.
Basically, they are just explaining that Area = L · W, and to check both options to see if there is an answer.
For the first question, simply draw a horizontal line that has a middle number of 0. This is our number line. Then simplify plot the points.
For example, Furyk will be -3. Because he is 3 under par and par is 0.
For the second question, just find each person's score and line them up by size.
Furyk: -3
Woods: -6
Daly: +1
Couples: +6
Rearrange them by size.
-6, -3, 1, 6
And for the last question, Furyk would have a coordinate of (-3, 0).
So, the integers and the whole number would be the answer.
The correct answer is 1. Hope this helps.
