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Zina [86]
3 years ago
5

Nikki is building a wall with bricks. Each brick is 10 inches long. The bricks are laid end-to-end, and one inch of mortar is la

yered between each brick.
a. Write and equation to model the number of bricks, N, Nikki needs in each layer to build a wall 10 feet long.


b. Solve the equation and state your result in words.
Mathematics
1 answer:
Alla [95]3 years ago
4 0

Answer:

b = 11

11 bricks will be required with 10 (1 inch motar) in between the bricks.

Step-by-step explanation:

Given the following :

Length of brick = 10 inches long

Between each laid brick, there is an inch of mortar layered before the next brick.

Number of bricks needed to build a wall which is 10 feets long.

Converting from feet to inch :

1 foot = 12 inches

Hence,

10 feets = (10 × 12) = 120 inches (length of wall).

Hence number of bricks needed in each layer :

Total length of b, bricks = length per brick × b = 10b

Since mortar is laid in between any two bricks, then length of mortar for b, number of bricks will be (b-1) inches

Since the total length of wall to be constructed is 120 inches ;

Then the equation required =

Sum of brick length + mortar = 120 inches

10 b + (b - 1) = 120

11b - 1 = 120

Hence,

11b = 120 + 1

11b = 121

b = 121 / 11

b = 11

Number of mortar = (b - 1) = - 11 - 1 = 10

Hence, 11 bricks will be required with 10 (1 inch motar) in between the bricks.

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Answer:

The distance (d) between two points (x1,y1) and (x2,y2) is given by the formula

d = √  ((X2-X1)2+(Y2-Y1)2)

d = √ (5-2)2+(3-8)2

d = √ ((3)2+(-5)2)

d = √ (9+25)

d = √ 34

The distance between the points is 5.8309518948453

The midpoint of two points is given by the formula

Midpoint= ((X1+X2)/2,(Y1+Y2)/2)

Find the x value of the midpoint

Xm=(X1+X2)/2

Xm=(2+5)/2=3.5

Find the Y value of the midpoint

Ym=(Y1+Y2)/2

Ym=(8+3)/2=5.5

The midpoint is: (3.5,5.5)

Graphing the two points, midpoint and distance

P1 (2,8)

P2 (5,3)

Midpoint (3.5,5.5)

The length of the black line is the distance between the points (5.8309518948453)

Find the slope of the line connecting the two points

Slope =  (Y2-Y1)  =  (3-8)  =  (-5)  = -1.66666666666667

(X2-X1) (5-2) (3)

Find the equation of the line passing through the two points

The general equation for a straight line is

y = mx + b

Where m represents the slope of the line which we found in the previous step to be -1.66666666666667

y = -1.67x + b

We substitute x and y for the values from one of our points (2,8)

8 = -1.67×2 + b

8 = -3.33 + b

8--3.33 = b

11.33 = b

Knowing both b and m, we can contruct the equation of the line

y= -1.67x+ 11.33

X and Y intercepts

The x-intercept is a point on the graph where y is zero

Using the equation we found in the previous step and substituting zero for y

y= -1.67x+ 11.33

0= -1.67x+ 11.33

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The x intercept for this straight line is 6.80

The y-intercept is a point on the graph where x is zero

Using the equation we found in the previous step and substituting zero for x

y= -1.67×0+ 11.33

y= 11.33

The y intercept for this straight line is 6.80

References

refernce image showing the distance between two points on the xy plane

Step-by-step explanation:

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