2 years ago

At the carnival the ratio of people who won the ring toss game to lost it 5 : 3. If 45 people won, how many people would of lost

Mathematics

2 answers:

Eva8 [605]2 years ago

5 0

The answer is 9

5 : 3 1

10: 6 2

15 : 9 3

20 : 12 4

25 : 15 5

30 : 18 6

35 : 21 7

40: 24 8

45 : 27 9

(I'm not the best at explaining)

REY [17]2 years ago

4 0

5 win : 3 lost

*9 *9

------- -----------

45 win : 27 lost

Answer: 27 lost

You might be interested in

Guided Practice

3241004551 [841]

Answer: y( 1 - 7y2 + 15y7)

Step-by-step explanation:Just put () around the 1 threw 15 and put the y out of the ()

5 0

2 years ago

Read 2 more answers

Jenna bought a bike for $200. The value of the bike decreases by 5% each year. Write an equation to model the situation.

bazaltina [42]

I'm not sure if this is correct.

200/5x

8 0

2 years ago

Read 2 more answers

Write an equation in slope-intercept form for the line with slope -6 and y-intercept 5

algol [13]

Answer:

y=-6+5

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Prove 2√(x) + 1/√(x + 1) <= 2√(x+1) for all x in [0,inf)

EleoNora [17]

Start by multiplying each side of the inequality by $\sqrt{x + 1}$ and simplifying:

$2 \sqrt x + \frac{1}{\sqrt{x+1}} \leq 2 \sqrt{x + 1}$
$(2 \sqrt x + \frac{1}{\sqrt{x+1}})(\sqrt{x + 1}) \leq (2 \sqrt{x + 1})(\sqrt{x + 1})$
$2 \sqrt{x(x + 1)} + 1 \leq 2(x + 1)$
$2 \sqrt{x^2 + x} + 1 \leq 2x + 2$
$2 \sqrt{x^2 + x} \leq 2x + 1$
$\sqrt{x^2 + x} \leq x + \frac{1}{2}$

From here, we can square both sides to get

$x^2 + x \leq (x + \frac{1}{2})^2$
$x^2 + x \leq x^2 + x + \frac{1}{4}$
$0 \leq \frac{1}{4}$ , which is always true.

3 0

2 years ago

The mean score on biology quiz was 62 with a standard deviation of 8, Jose’s score was a 74% what was his z score?

melisa1 [442]

(74-62)/8=3/2=1.5
Thank you hope this helps

7 0

2 years ago