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3 years ago

10

What is the equation of the line shown in the graph? Write the equation in standard form.

1 answer:

spin [16.1K]3 years ago

6 0

-1= -y is the answer in standard form while y=1 is the slope intercept form

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The scale in the drawing is 2 inches : 3 feet. What are the length and width of the actual room? *

patriot [66]

drawing isn't shown, pls take a screenshot or photograph the exercise

5 0

3 years ago

Find the midpoint of the segment between the points (17,−11) and (−14,−16)

Viefleur [7K]

Answer:

(1.5, -13.5)

Step-by-step explanation:

Midpoint Formula: $(\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )$

Simply plug in our coordinates into the formula:

x = (17 - 14)/2

x = 3/2

y = (-11 - 16)/2

y = -27/2

4 0

3 years ago

Read 2 more answers

The indefinite integral can be found in more than one way. First use the substitution method to find the indefinite integral. Th

Fantom [35]

Answer:

∫ $6x^5(x^6-2)\,dx$ = $\frac{1}{2}(x^6-2)^2+C$

Step-by-step explanation:

To find:

∫ $6x^5(x^6-2)\,dx$

Solution:

Method of substitution:

Let $x^6-2=t$

Differentiate both sides with respect to $t$

$6x^5\,dx=dt$

[use $(x^n)'=nx^{n-1}$ ]

So,

∫ $6x^5(x^6-2)\,dx$ = ∫ $t\,dt$ = $\frac{t^2}{2}+C_1$ where $C_1$ is a variable.

(Use ∫ $t^n\,dt=\frac{t^{n+1} }{n+1}$ )

Put $t=x^6-2$

∫ $6x^5(x^6-2)\,dx$ = $\frac{1}{2}(x^6-2)^2+C_1$

Use $(a-b)^2=a^2+b^2-2ab$

So,

∫ $6x^5(x^6-2)\,dx$ = $\frac{1}{2}(x^6-2)^2+C_1=\frac{1}{2}(x^{12}+4-4x^6)+C_1=\frac{x^{12} }{2}-2x^6+2+C_1=\frac{x^{12} }{2}-2x^6+C$

where $C=2+C_1$

Without using substitution:

∫ $6x^5(x^6-2)\,dx$ = ∫ $6x^{11}-12x^5\,dx$ = $\frac{6x^{12} }{12}-\frac{12x^6}{6}+C=\frac{x^{12} }{2}-2x^6+C$

So, same answer is obtained in both the cases.

7 0

3 years ago

Factoring Quadratic Expressions:<br> 5p^2 - p - 18

Dennis_Churaev [7]

$5 p^{2} -p-18$

$5 p^{2}-10p+9p-18$

$5p(p-2)+9(p-2)$

$(p-2)(5p+9)$

3 0

3 years ago

Nutka1998 [239]

Answer: Picking the first option and constantly adding on and on you will eventually make way more than what the second option proposes, therefore picking the first option is the obvious choice.

Step-by-step explanation:

Well let’s see it starts off slow for instance 1, 2, 4, 8, 16 and so on adding that on for a month will eventually leave you with more.

4 0

3 years ago