Part I: Find the measure of FED and the measure of ZDEN . Give an explanation for each angle

Can someone pls help me with question 7 :(<br> Ignore above text x

cricket20 [7]

Answer: x= 30 because the elevated point is 25 degrees and if you add it with 110 and subtract it with 35 you get 110 + 25 = 135 and 35 - 25 = 15 135 + 15 = 150 and 180 - 150 = 30. so it is 30 degrees. (tell me if i was wrong cause i'm 90% sure this is it but i don't know.)

6 0

3 years ago

What is the value of x in the diagram below? 2 right triangles are stacked. The bottom triangle has a side length of 9 units and

ehidna [41]

Answer:

18 sqrt2/ sqrt3

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

1.4t-0.4(t-3.1)=5.8 please help !!

Svetllana [295]

Okay so i cant just post what the answer is i have to type something.
but anyways this is the answer: t= 4.56

4 0

3 years ago

You are jumping off the 12 foot diving board at the municipal pool. You bounce up at 6 feet per second and drop to the water you

NARA [144]

Answer:

When do you hit the water?

1.075 seconds after you jump.

What is your maximum height?

the maximum height is 12.5626 ft

Step-by-step explanation:

The equation:

h(t) = -16*t^2 + 6*t + 12

Is the height as a function of time.

We know that the initial height is the height when t = 0s

h(0s) = 12

and we know that the diving board is 12 foot tall.

Then the zero in h(t)

h(t) = 0

Represents the surface of the water.

When do you hit the water?

Here we just need to find the value of t such that:

h(t) = 0 = -16*t^2 + 6*t + 12

Using the Bhaskara's formula, we get:

$t = \frac{-6 \pm \sqrt{6^2 - 4*(-16)*12} }{2*(-16)} = \frac{-6 \pm 28.4}{-32}$

Then we have two solutions, and we only care for the positive solution (because the negative time happens before the jump, so that solution can be discarded)

The positive solution is:

t = (-6 - 28.4)/-32 = 1.075

So you hit the water 1.075 seconds after you jump.

What is your maximum height?

The height equation is a quadratic equation with a negative leading coefficient, then the maximum of this parabola is at the vertex.

We know that the vertex of a general quadratic:

a*x^2 + b*x + c

is at

x = -b/2a

Then in the case of our equation:

h(t) = -16*t^2 + 6*t + 12

The vertex is at:

t = -6/(2*-16) = 6/32 = 0.1875

Evaluating the height equation in that time will give us the maximum height, which is:

h(0.1875) = -16*(0.1875 )^2 + 6*(0.1875) + 12 = 12.5626

And the height is in feet, then the maximum height is 12.5626 ft

6 0

3 years ago

Points A(−1.5) and B(6) are marked on a number line. Find the coordinate of point M if it is known that AM:MB=1:2. Find all poss

stellarik [79]

<span>M can have a coordinate of (-9) or (1) There are potentially 3 different places for point M to go. It can be placed to the left of point A, between points A and B, and to the right of point B. Let's check those three possibilities. 1. Left of point A. This works if the distance between M and A is the same as the distance between A and B. So distance between A and B = 6 - (-1.5) = 6 + 1.5 = 7.5 So the location for M would be -1.5 - 7.5 = -9 So point M can have the value of -9. 2. Between A and B. This would also work. Since we want a 1:2 ratio, place M one third of the way from A to B. Since we already know the distance between A and B to be 7.5, that means that we should add 7.5/3 = 2.5 to the value of A. So -1.5 + 2.5 = 1 So point M can also have the value of 1. 3. To the right of point B This won't work. Point B will always be closer to M than point A will be. So it's impossible to get a ratio of 1:2.</span>

5 0

3 years ago