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ser-zykov [4K]
3 years ago
9

When a number is divided by -3, the result is 12 more than the number what is the number?

Mathematics
1 answer:
olga55 [171]3 years ago
8 0
X/-3 = 12 + x
x = -36 - 3x
4x = 36
x= = 9

The number is 9.

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The graph of a line has a slope of -3 and passes through the point (-6,-4).
prohojiy [21]

Answer:

(A) y+4=-3(x+6)

Step-by-step explanation:

The point-slope form of the equation of a line whose slope is m and passes through the point (x_1, y_1) is: y-y_1=m(x-x_1)

Given the point: (x_1, y_1)=(-6,-4)

Slope, m=-3

x_1=-6\\y_1=-4

Substituting these values into:  y-y_1=m(x-x_1), we obtain the point slope form of the equation:

y-(-4)=-3(x-(-6))\\\\y+4=-3(x+6)

The correct option is A.

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Delaware was the first state to enter the Union and Hawaii was the 50th. If we order the positions of entry for the rest of the
Anna71 [15]

Answer:

State A was the <u>12th</u> state to enter the Union. State B was the <u>11th</u> state to enter the Union.

Step-by-step explanation:

Let's call x to the order-of-entry of State B, therefore the order-of-entry of State A is x+1. Given that he product of their order-of-entry numbers is 132:

x*(x+1) = 132

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Using quadratic formula:

x = \frac{-b \pm \sqrt{b^2 -4(a)(c)}}{2(a)}

x = \frac{-1 \pm \sqrt{1^2 -4(1)(-132)}}{2(1)}

x = \frac{-1 \pm 23}{2}

x_1 = \frac{-1 + 23}{2}

x_1 = 11

x_2 = \frac{-1 - 23}{2}

x_2 = -12

The negative solution has no sense in the context of our problem, then the solution is x = 11.

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Answer:

the test I will perform is d. ​​Two-sided t-test

Step-by-step explanation:

When we are to compare between different data, critical regions occur on both sides of the  mean of a normal distribution,they are as a result of two-tailed or two-sided tests.

In such tests, consideration has to be given to values  on both sides of the mean.

for this question, it is expected to compare weather it is true that first born have different intelligent or not, weather to accept a null hypothesis or reject.

For example, if it is  required to show that the percentage of metal, p, in a

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