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denis23 [38]
3 years ago
13

Plz solv this please guys

Mathematics
2 answers:
exis [7]3 years ago
5 0

Answer:

x is 130 degrees. y is 80 degrees.

Step-by-step explanation:

padilas [110]3 years ago
5 0

Step-by-step explanation:

since ABCD is a Rhombus, x = 180-50 = 130°

y = 180-(50+50)= 80°

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Which type(s) of symmetry does the following object have? Select all that apply.​
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vertical line of symmetry. if you split the shape in the middle, the two pieces would be the same. it also has rotational symmetry because if you rotate it, it would still look the same and be the same shape.

It does not have horizontal or diagonal symmetry because if you split it those ways, the two pieces made will be different. Because it has rotational and vertical symmetry, it does not have "no symmetry"

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Algebra 1 Honors
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brainliest if correct

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(x/x+3)-(8/x+2)=(-13x-6)/(x^2+5x+6)​
Fed [463]

Answer:

x = -9

x = 2

Step-by-step explanation:

Given:

\dfrac{x}{x+3}-\dfrac{8}{x+2}=\dfrac{-13x-6}{x^2+5x+6}

First, note that

x^2+5x+6=x^2+2x+3x+6=x(x+2)+3(x+2)=(x+2)(x+3)

Since x+2 and x+3 stay in the denominator, then

x\neq -2\ \text{and}\ x\neq -3

Now add two fractions which stay in the left part. The common denominator is (x+2)(x+3), so multiply the numerator of the first fraction by (x+2) and the numerator of the second fraction by (x+3) and subtract them in the numerator:

\dfrac{x}{x+3}-\dfrac{8}{x+2}=\dfrac{-13x-6}{(x+2)(x+3)}\\ \\\dfrac{x(x+2)-8(x+3)}{(x+2)(x+3)}=\dfrac{-13x-6}{(x+2)(x+3)}\\ \\x(x+2)-8(x+3)=-13x-6\\ \\x^2+2x-8x-24=-13x-6\\ \\x^2+2x-8x+13x-24+6=0\\ \\x^2+7x-18=0\\ \\x^2+9x-2x-18=0\\ \\x(x+9)-2(x+9)=0\\ \\(x+9)(x-2)=0\\ \\x+9=0\ \text{or}\ x-2=0\\ \\x=-9\ \text{or}\ x=2

3 0
3 years ago
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