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yawa3891 [41]
2 years ago
13

The ratio of sugar to flour is 2:3. If there are 6 cups of sugar, how many cups of flour are there

Mathematics
2 answers:
lesantik [10]2 years ago
8 0
The answer would be 9 cups of flour
Paul [167]2 years ago
8 0
(5/1)=(2/x)
cross multiply
5x=2x1
simplify
5x=2
divide each side by 5 to find x
x=2/5
2/5 or 0.4 cups of flour are needed
answer= 2/5
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At a 3​-mile ​cross-country race, an athlete runs 2 miles at 6 mph and 1 mile at 12 mph. What is the​ athlete's average​ speed?
Tom [10]

Answer: the average speed is 7.5 mph or at least im pretty sure

Step-by-step explanation:

This is because if you make the 2 miles at 6 mph to 1 mile at 3 mph then you get 1 mile at 3mph and 1 mile at 12 mph. now that you have the unit rates of these you can add them. 1 + 1 = 2 miles and 3 + 12 = 15 mph now divide this by two and you get 7.5 mph per mile.

I hope this helped, if it did could you give me a good rating? lol

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2 years ago
From a cuboidal cardboard box of dimensions 80cm×40cm×15cm,6 circles of radius 7 cm were cut from the front face.Find the surfac
Irina-Kira [14]

Answer:

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6 0
2 years ago
Which statement is true regarding the functions on the
prisoha [69]

Answer:

f(2) = g(2)

General Formulas and Concepts:

<u>Alg I</u>

  • Reading a Cartesian Plane
  • Identifying Coordinates
  • Solutions of systems of equations

Step-by-step explanation:

We see from the graph that f(x) and g(x) intersect at x = 2. Therefore, the point at x = 2 would be equivalent in both graphs/be a solution to both equations.

Therefore, f(2) must equal g(2), as they intersect each other at that point and have the same value of 0.

3 0
2 years ago
f the price charged for a candy bar is​ p(x) cents, where p (x )equals 162 minus StartFraction x Over 10 EndFraction ​, then x t
andreev551 [17]

Answer:

a. 1620-x^2

b. x=810

c. Maximum value revenue=$656,100

Step-by-step explanation:

(a) Total revenue from sale of x thousand candy bars

P(x)=162 - x/10

Price of a candy bar=p(x)/100 in dollars

1000 candy bars will be sold for

=1000×p(x)/100

=10*p(x)

x thousand candy bars will be

Revenue=price × quantity

=10p(x)*x

=10(162-x/10) * x

=10( 1620-x/10) * x

=1620-x * x

=1620x-x^2

R(x)=1620x-x^2

(b) Value of x that leads to maximum revenue

R(x)=1620x-x^2

R'(x)=1620-2x

If R'(x)=0

Then,

1620-2x=0

1620=2x

Divide both sides by 2

810=x

x=810

(C) find the maximum revenue

R(x)=1620x-x^2

R(810)=1620x-x^2

=1620(810)-810^2

=1,312,200-656,100

=$656,100

7 0
3 years ago
Does 14 and 10 have the same factor
iVinArrow [24]

Answer:

Yes

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4 0
2 years ago
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