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liraira [26]
3 years ago
9

Suppose a shipment of 170 electronic components contains 3 defective components. to determine whether the shipment should be​ ac

cepted, a​ quality-control engineer randomly selects 3 of the components and tests them. if 1 or more of the components is​ defective, the shipment is rejected. what is the probability that the shipment is​ rejected?
Mathematics
1 answer:
lbvjy [14]3 years ago
7 0
If nCk represents the number of ways k parts can be chosen from a pool of n, the probability of interest is the complement of the probability of selecting all good parts.
  1 - (167C3)/(170C3) = 42,085/804,440 ≈ 0.0523

_____
nCk = n!/(k!(n-k)!)
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Find the unknown factor.
pshichka [43]
The answers is -7/6x
3 0
2 years ago
The plus minus of a player for the first forty games of the season is listed below. A plus when is your team scored more
Tamiku [17]

Answer:

take the population mean divided by four

Step-by-step explanation:

4 0
3 years ago
Suppose you wish to borrow $600 for two weeks and the amount of interest you must pay is $25 per $100 borrowed. What is the APR
Yuliya22 [10]

Answer:

The APR at which the money is borrowed, is approximately 651.79%

Step-by-step explanation:

The amount which one wishes to borrow for two weeks, P = $600

The amount of interest that one must pay back = $25 per $100 borrowed

Therefore;

The total interest on the $600 loan (borrowed) for two weeks = 25/100× $600 = $150

The number of days for which the amount was borrowed = 2 weeks = 14 days

The Annual Percentage Rate, APR is given as follows;

APR = \left (\dfrac{\left (\dfrac{Interest \ Paid \ for \ the  \ Loan \ duration}{The \ amount \ borrowed} \right )}{The \ number \ of \ days \ the \ amount \ was  \ borrowed } \right ) \times 365 \times 100

Therefore, we get

APR = \left (\dfrac{\left (\dfrac{150}{600} \right )}{14 } \right ) \times 365 \times 100  \approx 651.79 \%

The annual rate at which the money is borrowed, APR ≈ 651.79%.

8 0
3 years ago
A company that rents small moving trucks wants to purchase 25 trucks with a combined capacity of 28,000 cubic feet. Three differ
pickupchik [31]

Answer:

We have 4 solutions:

  • No 10-foot truck, 10  14-foot trucks, and 15 24-foot trucks
  • 2 10-foot trucks, 7 14-foot trucks, and 16 24-foot trucks
  • 4 10-foot trucks, 4  14-foot trucks, and 17 24-foot trucks
  • 6 10-foot trucks, 1 14-foot trucks, and 18 24-foot trucks

Step-by-step explanation:

Let the number of 10-foot truck with a capacity of 350 cubic feet purchased=a

Let the number of 14-foot truck with a capacity of 700 cubic feet purchased=b

Let the number of 24-foot truck with a capacity of 1,400 cubic feet purchased=c

The company wants to purchase 25 trucks, therefore.

  • a+b+c=25

Furthermore, the combined capacity of the trucks is 28,000 cubic feet.

  • 350a+700b+1400c=28000

Since the number of equations is less than the number of variables, you can not use a matrix equation to solve this problem.  The solution is most easily found using an augmented matrix.  

The augmented matrix is presented below:  

\left[\begin{array}{ccc|c}1&1&1&25\\350&700&1400&28000\end{array}\right]

Using the calculator, the reduced row echelon form is:

\left[\begin{array}{ccc|c}1&0&-2&-30\\0&1&3&55\end{array}\right]

where  

a- 2c=-30 means a =2c-30

b+3c=55 means b= 55-3c

We alter the value of c as long as neither a nor b becomes negative. Suitable values for c are 15, 16, 17, and 18:

\left|\begin{array}{|c||c||c|}a=2c-30&b=55-3c&c\\0&10&15\\2&7&16\\4&4&17\\6&1&18\end{array}\right|

We can easily  verify that, for each solution, the number of trucks adds up to 25 and the fleet capacity is 28,000 cubic feet.

We therefore have 4 solutions:

  • No 10-foot truck, 10  14-foot trucks, and 15 24-foot trucks
  • 2 10-foot trucks, 7 14-foot trucks, and 16 24-foot trucks
  • 4 10-foot trucks, 4  14-foot trucks, and 17 24-foot trucks
  • 6 10-foot trucks, 1 14-foot trucks, and 18 24-foot trucks
4 0
3 years ago
Can someone please explain this for me, thank you.
r-ruslan [8.4K]

just divide Atlantic/Mississippi

\frac{3.1 \times  {10}^{17} }{6.3 \times  {10}^{11} }  =  \frac{3.1}{6.3}  \times  \frac{ {10}^{17} }{ {10}^{11} }  \\  = 0.492 \times  {10}^{17 - 11}  \\  = 0.492 \times  {10}^{6}  \\  = 4.92 \times  {10}^{5}

7 0
3 years ago
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