Step-by-step explanation:
▪ x - 3 < 3x - 7
▪ x + 4 < 3x
▪ 4 < 2x
▪ 2 < x
Answer:
What is the sample variance of bottle weight 2.33
Step-by-step explanation:
First find the mean. The mean of the bottle weight is obtained by taking the ratio of the sum of ages and total number of ages.
Mean = (4+2+5+4+5+2+6) / 7
= 28 / 7
= 4
Sample Variance = ![\frac{\left[\begin{array}{ccc}(4-4)^{2} +(2-4)^{2} +\\(5-4)^{2} + (4-4)^{2} +\\(5-4)^{2} + (2-4)^{2} +\\(6-4)^{2}\end{array}\right]}{7-1}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%284-4%29%5E%7B2%7D%20%2B%282-4%29%5E%7B2%7D%20%2B%5C%5C%285-4%29%5E%7B2%7D%20%2B%20%284-4%29%5E%7B2%7D%20%2B%5C%5C%285-4%29%5E%7B2%7D%20%2B%20%282-4%29%5E%7B2%7D%20%2B%5C%5C%286-4%29%5E%7B2%7D%5Cend%7Barray%7D%5Cright%5D%7D%7B7-1%7D)
=
= 2.33
Answer:
is this a multiple answer question
Step-by-step explanation:
So, I came up with something like this. I didn't find the final equation algebraically, but simply "figured it out". And I'm not sure how much "correct" this solution is, but it seems to work.
![f(x)=\sin(\omega(x))\\\\f(\pi^n)=\sin(\omega(\pi^n))=0, n\in\mathbb{N}\\\\\\\sin x=0 \implies x=k\pi,k\in\mathbb{Z}\\\Downarrow\\\omega(\pi^n)=k\pi\\\\\boxed{\omega(x)=k\sqrt[\log_{\pi} x]{x},k\in\mathbb{Z}}](https://tex.z-dn.net/?f=f%28x%29%3D%5Csin%28%5Comega%28x%29%29%5C%5C%5C%5Cf%28%5Cpi%5En%29%3D%5Csin%28%5Comega%28%5Cpi%5En%29%29%3D0%2C%20n%5Cin%5Cmathbb%7BN%7D%5C%5C%5C%5C%5C%5C%5Csin%20x%3D0%20%5Cimplies%20x%3Dk%5Cpi%2Ck%5Cin%5Cmathbb%7BZ%7D%5C%5C%5CDownarrow%5C%5C%5Comega%28%5Cpi%5En%29%3Dk%5Cpi%5C%5C%5C%5C%5Cboxed%7B%5Comega%28x%29%3Dk%5Csqrt%5B%5Clog_%7B%5Cpi%7D%20x%5D%7Bx%7D%2Ck%5Cin%5Cmathbb%7BZ%7D%7D)