Plz help!!! marking brainiest!!

Whats 16 = k/11<br>and v/8=2

Dvinal [7]

$16= \frac{k}{11} 
\\16*11=k
\\k=176

$

$\frac{v}{8} =2
\\v=8*2
\\v=16$

6 0

3 years ago

Determine the 30th term of the sequence -10 -15 -20

creativ13 [48]

190. Count it out on your fingers, starting with -10,-15, and -20. Then count out both hands.

3 0

3 years ago

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Suppose that the area between a pair of concentric circles is 49pi. Find the length of a chord in the larger circle that is tang

Lapatulllka [165]

Answer:

14 units

Step-by-step explanation:

We are given that the area between two concentric circles is $49\pi$

We have to find the length of chord in the larger circle that is tangent to the smaller circle.

Let $r_1,r_2$ be the radius of two circles.

$r_1$ be the radius of small circle and $r_2$ be the radius of large circle

We know that area pf circle= $\pi r^2$

Area of large circle = $\pi r^2_2$

Area of small circle = $\pi r^2_1$

Area between two circles = $49\pi$

Area of large circle -Area of small circle= $49\pi$

$\pi r^2_2-\pi r^2_1=49\pi$

$\pi(r^2_2-r^2_1)=49$

By pythagorus theorem

$AD^2=OA^2-OD^2$

$AD^2=r^2_2-r^2_1$

$AD=49$

$AD=\sqrt{49}=7$

Length of chord= $2\cdot AD$

Hence, the length of chord of the larger circle = $2\cdot7=14$ units

7 0

3 years ago

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Find the distance between the points. A(3, 0) and B((8,10)

kap26 [50]

Answer:

The distance is 5 square root of 5, or if it asks in decimal form it would be 11.180.

Step-by-step explanation:

To find the distance between any points, you must use the distance formula. When you plug in the points given, you end up with 11.180. I hope this helps!

6 0

3 years ago

write an equation for an ellipse centered at the origin, which has foci at (+-3,0) and co vertices at (0+-4)

natali 33 [55]

Answer:

The equation for an ellipse centered at the origin with foci at (-3, 0) and (+3, 0) and co-vertices at (0, -4) and (0, +4) is:

$\frac{x^{2}}{7} + \frac{y_{2}}{16} = 1$

Step-by-step explanation:

An ellipse center at origin is modelled after the following expression:

$\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1$

Where:

$a$ , $b$ - Major and minor semi-axes, dimensionless.

The location of the two co-vertices are (0, - 4) and (0, + 4). The distance of the major semi-axis is found by means of the Pythagorean Theorem:

$2\cdot b = \sqrt{(0-0)^{2}+ [4 - (-4)]^{2}}$

$2\cdot b = \pm 8$

$b = \pm 4$

The length of the major semi-axes can be calculated by knowing the distance between center and any focus (c) and the major semi-axis. First, the distance between center and any focus is determined by means of the Pythagorean Theorem:

$2\cdot c = \sqrt{[3 - (-3)]^{2}+ (0-0)^{2}}$