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photoshop1234 [79]
3 years ago
10

The table below shows two equations:

Mathematics
2 answers:
ra1l [238]3 years ago
6 0
The correct answer is option A A) Equation 1 and equation 2 have no solutions For the equation 1 l 3x-1 l +7=2 l 3x-1 l = 2-7 =-5 The absolute value should be positive So, there is no solution For the equation 2 l 2x+1 l +4 = 3 l 2x+1 l = 3 - 4= -1 The absolute value should be positive So, there is no solution
Hitman42 [59]3 years ago
6 0
The correct answer is A)

The proof for the veracity is that we have these two equations:

(1) \left | 3x-1 \right |+7=2

∴ \left | 3x-1 \right |=-5

(2) \left | 2x+1 \right |+4=3

∴ \left | 2x+1 \right |=-1

Given that because of the property of Absolute Value Function \left | 3x-1 \right |\geq0 and \left | 2x+1 \right | \geq 0 (it must be so) then there is not possible for the equation (1) and (2) to be true.

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6 0
3 years ago
What is the completely factored form of x4y – 4x2y – 5y?
Lady_Fox [76]
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The correct result would be <span>y * (x^2 + 1) * (x^2 - 5).</span>
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