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DanielleElmas [232]
3 years ago
7

Apply the distributive property to write an equivalent expression in expanded form

Mathematics
2 answers:
iVinArrow [24]3 years ago
7 0
YES! It can when you write your distributive property problem just expand it out by each part.
irakobra [83]3 years ago
3 0
I agree distributive property and expanding is key in these equations


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A polygon’s interior angles sum to 3600 degrees. How many sides does it have?
Sergeeva-Olga [200]

Answer:

5

Step-by-step explanation:

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3 years ago
G(x) = 15 – 4x<br> h(x) = x +8<br> Write g(h(x)) as an expression in terms of 2.
Sergeu [11.5K]

For this case we have the following functions:

g (x) = 15-4x\\h (x) = x + 8

We must findg (h (x))when x = 2.

So:

g (h (x)) = 15-4 (x + 8) =

We apply distributive property to the terms within parentheses taking into account that:

- * + = -\\15-4x-32 =

We add similar terms taking into account that different signs are subtracted and the sign of the major is placed:

-17-4x

Thus, we have to:

g (h (x)) = - 17-4x

Then, with x = 2:

g (h (2)) = - 17-4 (2) = - 17-8 = -25

Equal signs are added and the same sign is placed.

Answer:

g (h (2)) = - 25

3 0
3 years ago
Draw a rough sketch of a quadrilateral KLMN. State, (a) two pairs of opposite sides, (b) two pairs of opposite angles, (c) two p
kogti [31]

Answer:

Please find attached the drawing of quadrilateral KLMN created with MS Whiteboard using the Ink to Shape command

(a) Two pairs of opposite sides are \overline {KN}, \overline {LM} and \overline {KL}, \overline {NM}

(b) Two pairs of opposite angles are ∠LKN, ∠LMN, and ∠KLM and ∠KNM

(c) Two pairs of adjacent sides are \overline {KN}, \overline {NM} and \overline {KL}, \overline {LM}

(d) Two pairs of adjacent angles are ∠LKN, ∠KLM and ∠LMN, ∠KNM

Step-by-step explanation:

7 0
3 years ago
HELP PLEAAAASEE!!!!!!!!!!
Anuta_ua [19.1K]

Answer:

D

Step-by-step explanation:

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5 0
3 years ago
A spring has natural length 20 cm. Compare the work W1 done in stretching the spring from 20 cm to 30 cm with the work W2 done i
sashaice [31]

Answer:

W1 = W2 = 50k Joules (assuming W1 and W2 have the same force constant, k)

W1 - W2 = 0

Step-by-step explanation:

Work done in stretching a spring is given by 1/2ke^2

Where, k is force constant and e is extension

e1 = 30cm - 20cm = 10cm

W1 = 1/2k(e1)^2 = 1/2×k×10^2 = 50k Joules

e2 = 40cm - 30cm = 10cm

W2 = 1/2k(e2)^2 = 1/2×k×10^2 = 50k Joules

W1 = W2 = 50k Joules provided W1 and W2 have equal force constant

Therefore, W1 - W2 = 0

7 0
3 years ago
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