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irga5000 [103]
3 years ago
9

Can the sides of a right triangle have sides the length of 48.5ft,30ft,32.5ft

Mathematics
1 answer:
myrzilka [38]3 years ago
8 0

Answer:

No

Step-by-step explanation:

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Joanie runs the concession stand for the school's baseball games. At each game, the best selling items are pretzels and hot dogs
STALIN [3.7K]
77 because add them all up then subtract 14
3 0
3 years ago
The ages of five friends are 25, 36, 33, 36 and 30 how many of friends are older than the average (arithmetic mean) age?
Murrr4er [49]

Answer:

3 friends are older than the average.

Step-by-step explanation:

First find the mean. The mean can be found adding all the numbers in the set together and dividing by the amount of numbers in the giving set:

(25 + 36 + 33 + 36 + 30)/5 = (160)/5 = 32

The average age is 32. There are 3 friends that are older than the average (33 , 36 , 36, respectfully).

~

4 0
2 years ago
2y + 4x = 16<br><br> Anyone know how to solve for Y?
Ede4ka [16]

Answer:

y = -2x + 8

Step-by-step explanation:

In this question, you have to solve for "y".

Solve:

2y + 4x = 16

Get "y" by itself by subtracting 4x from both sides.

2y = -4x + 16

Simplify by dividing both sides by 2.

y = -2x + 8

3 0
3 years ago
Read 2 more answers
Tensile-strength tests were carried out on two different grades of wire rod. Grade 1 has 10 observations yielding a sample mean
LuckyWell [14K]

Answer:

t = \frac{1085-1034}{\sqrt{\frac{52^2}{10} +\frac{61^2}{15}}} = 2.240

df = n_1 +n_2 -2 = 10+15-2= 23

p_v = 2*P(t_{23} >2.240) = 0.035

Since the p value is lower than the significance level we have enough evidence to conclude that the true means are different at 5% of significance

Step-by-step explanation:

Data given

\bar X_1 = 1085 sample mean for group 1

\bar X_2 = 1034 sample mean for group 2

n_1 = 10 sample size for group 1

n_2 = 15 sample size for group 2

s_1 = 52 sample deviation for group 1

s_2 = 61 sample deviation for group 2

Solution

We want to check if the two means are equal so then the system of hypothesis are:

Null hypothesis: \mu_1= \mu_2

Alternative hypothesis: \mu_1 \neq \mu_2

And the statistic is given by:

t = \frac{\bar X_1 -\bar X_2}{\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}}

And replacing we got:

t = \frac{1085-1034}{\sqrt{\frac{52^2}{10} +\frac{61^2}{15}}} = 2.240

The degrees of freedom are given by:

df = n_1 +n_2 -2 = 10+15-2= 23

And the p value would be:

p_v = 2*P(t_{23} >2.240) = 0.035

Since the p value is lower than the significance level we have enough evidence to conclude that the true means are different at 5% of significance

8 0
4 years ago
The sum of ten and the quotien of a number x and 6
Nana76 [90]
10+ x/6 i believe this is the answer
3 0
4 years ago
Read 2 more answers
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