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murzikaleks [220]

2 years ago

9

Select three common forms of Anglo-Saxon literature. lyric novella riddle epic elegy ballad novel short story

2 answers:

Solnce55 [7]2 years ago

8 0

Epic, elegy, and ballad are three common forms of Anglo-Saxon literature, whereas lyric, novella, riddle, novel, and short story were created much later.

Kipish [7]2 years ago

3 0

Answer:

The three common forms of Anglo-Saxon literature are:

<u>Epic, Ballad and Elegy.</u>

Step-by-step explanation:

Anglo-Saxon literature is covered since the fifth century in the Anglo-Saxon (Old English) period of Great Britain.

This literature covers genres as diverson as the epic, the ballad, the elegy, translations of the Bible and sermons.

-The epic is a genre that shows us legendary or fictional deeds of heroic feats whether real or imaginary in which they participated. An example is <em>Homer's Odyssey.</em>

-A ballad is a type of romantic song where musical tones are created from the writing of poems. Telling a person's life or some precise facts.

-The elegies are poems written in the first person, implying the ephemeral nature of joy, wealth and luck in life. These are works that fall into the sadness of the past. An example is <em>the elegy of The Wandering Man</em>.

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ONE HUNDRED POINTS

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Answer:

See Below.

Step-by-step explanation:

We are given that ∠A = ∠D, and we want to prove that ΔACB ~ ΔDCE.

Statements: Reasons:

$1) \text{ $\angle A=\angle D$}$ $\text{Given}$

$2) \text{ }\angle BCA=\angle ECD$ $\text{Vertical Angles Are Congruent}$

$3) \text{ } \Delta ACB \sim \Delta DCE$ $\text{AA (Angle-Angle) Similarity}$

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2 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

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Amy types at an average speed of 38 words per rinute. She has already typed 1,450 words of her final paper, which will be more t

34kurt

Answer: D. 38x + 1,450 > 4,000

Step-by-step explanation:

It has to be greater than 4,000 so A makes no sense

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8 0

2 years ago

Find the equation of the line that passes through point (7,5) and (-9,5)

Papessa [141]

Answer:

y = 5

Step-by-step explanation:

Calculate the slope m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (7, 5) and (x₂, y₂ ) = (- 9, 5)

m = $\frac{5-5}{-9-7}$ = $\frac{0}{-16}$ = 0

This means the line is horizontal and parallel to the x- axis with equation

y = c

where c is the value of the y- coordinates the line passes through.

The line passes through (7, 5) and (- 9, 5) with y- coordinates 5, thus

y = 5 ← equation of line

4 0

2 years ago

A plane is descending into the airport. After 5 minutes it is at a height of 6500 feet. After 7 minutes it is at a height of 590

Jet001 [13]

Let's assume

height of plane in feet =h

time in minutes =t

we are given

A plane is descending into the airport. After 5 minutes it is at a height of 6500 feet

so, we get one point as (5,6500)

After 7 minutes it is at a height of 5900 feet

so, we get another point as (7,5900)

we can use point slope form of line

$y-y_1=m(x-x_1)$

points as

(5,6500)

x1=5, y1=6500

(7,5900)

x2=7 , y2=5900

Calculation of slope(m):

$m=\frac{y_2-y_1}{x_2-x_1}$

now, we can plug values

$m=\frac{5900-6500}{7-5}$

$m=-300$

Equation of line:

we can use formula

$y-y_1=m(x-x_1)$

we can plug values

$h-6500=-300(t-5)$

$h=-300t+8000$

Time of landing:

we can set h=0

and then we can solve for t

$h=-300t+8000=0$

$t=\frac{80}{3}min$ ..............Answer

5 0

3 years ago