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3 years ago

Can someone help me out

Mathematics

2 answers:

dsp733 years ago

5 0

Answer:x value is 25

vesna_86 [32]3 years ago

4 0

Answer:

Step-by-step explanation:

x=30

2x=60

3x=90

30+60+90=180 degrees

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Drag each tile to the correct box.

Natasha_Volkova [10]

Answer:

1) Function h

interval [3, 5]

rate of change 6

2) Function f

interval [3, 6]

rate of change 8.33

3) Function g

interval [2, 3]

rate of change 9.6

Step-by-step explanation:

we know that

To find the average rate of change, we divide the change in the output value by the change in the input value

the average rate of change is equal to

$\frac{f(b)-f(a)}{b-a}$

step 1

Find the average rate of change of function h(x) over interval [3,5]

Looking at the third picture (table)

$f(a)=h(3)=4$

$f(b)=h(5)=16$

$a=3$

$b=5$

Substitute

$\frac{16-4}{5-3}=6$

step 2

Find the average rate of change of function f(x) over interval [3,6]

Looking at the graph

$f(a)=f(3)=10$

$f(b)=f(6)=35$

$a=3$

$b=6$

Substitute

$\frac{35-10}{6-3}=8.33$

step 3

Find the average rate of change of function g(x) over interval [2,3]

we have

$g(x)=\frac{1}{5}(4)^x$

$f(a)=g(2)=\frac{1}{5}(4)^2=\frac{16}{5}$

$f(b)=g(3)=\frac{1}{5}(4)^3=\frac{64}{5}$

$a=2$

$b=3$

Substitute

$\frac{\frac{64}{5}-\frac{16}{5}}{3-2}=9.6$

therefore

In order from least to greatest according to their average rates of change over those intervals

1) Function h

interval [3, 5]

rate of change 6

2) Function f

interval [3, 6]

rate of change 8.33

3) Function g

interval [2, 3]

rate of change 9.6

7 0

3 years ago

An elevator begins on the ground floor of a hotel. It travels up 18 floors, down 9 floors, up 5 floors, and down 3 floors. What

andrezito [222]

Answer:

Step-by-step explanation:

+18-9+5-3 = 11

It's on the eleventh floor and must go down 11 floors to return to the ground floor.

8 0

3 years ago

Use the net to find the surface area of the square pyramid.

lbvjy [14]

Answer: pay attern]dja]d

Step-by-step explanation:ad d ad ad adasd dad

3 0

3 years ago

Suppose that f(5) = 1, f '(5) = 4, g(5) = −8, and g'(5) = 7. Find the following values.

olya-2409 [2.1K]

I think G=50 because 5 times 10

5 0

3 years ago

Consider randomly selecting a student at a certain university, and let A denote the event that the selected individual has a Vis

ser-zykov [4K]

Answer:

a) $P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.3}{0.45}= 0.667$

Represent the probability that the event B occurs given that the event A occurs first

b) $P(B'|A) = \frac{0.15}{0.45}=0.333$

Represent the probability that the event B no occurs given that the event A occurs first

c) $P(A|B) = \frac{P(A \cap B)}{P(B)} = \frac{0.3}{0.35}= 0.857$

Represent the probability that the event A occurs given that the event B occurs first

d) $P(A'|B) = \frac{0.05}{0.35}=0.143$

Represent the probability that the event A no occurs given that the event B occurs first

Step-by-step explanation:

For this case we have the following probabilities given for the events defined A and B

$P(A) = 0.45, P(B) = 0.35, P(A \cap B) =0.30$

For this case we can begin finding the probability for the complements:

$P(B') =1-P(B) = 1-0.35= 0.65$

$P(A') =1-P(A) = 1-0.45= 0.55$

For this case we are interested on the following probabilities:

Part a

$P(B|A)$

For this case we can use the Bayes theorem and we can find this probability like this:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.3}{0.45}= 0.667$

Represent the probability that the event B occurs given that the event A occurs first

Part b

$P(B'|A) = \frac{P(B' \cap A)}{P(A}$

And for this case we can find $P(B' \cap A) =P(A) -P(A\cap B)= 0.45-0.3=0.15$

And if we replace we got:

$P(B'|A) = \frac{0.15}{0.45}=0.333$

Represent the probability that the event B no occurs given that the event A occurs first

Part c

$P(A|B) = \frac{P(A \cap B)}{P(B)} = \frac{0.3}{0.35}= 0.857$

Represent the probability that the event A occurs given that the event B occurs first

Part d

$P(A'|B) = \frac{P(A' \cap B)}{P(B}$

And for this case we can find $P(A' \cap B) =P(B) -P(A\cap B)= 0.35-0.3=0.05$

And if we replace we got:

$P(A'|B) = \frac{0.05}{0.35}=0.143$

Represent the probability that the event A no occurs given that the event B occurs first

3 0

3 years ago