Two identical boxes are being pulled across a horizontal floor at a constant velocity by a horizontal pulling force of 176 N tha
2 answers:
Answer:
the tension in the rope between the boxes is equal to 88 N
Explanation:
given,
the force applied on one body F = 176 N
When two bodies are moving on horizontal plane at constant velocity then their kinetic friction (f k) is equal to applied force F
According to newton third law the resultant force acting on one body is equal to the resultant force acting on the another body.
T is the tension in the rope
T - F = - (T - F)
T - 176 = - (T - 0)
2 T = 176
T = 176/2 = 88 N
so, the tension in the rope between the boxes is equal to 88 N
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Answer:
A) increase.
Explanation:
- By definition, the capacitance of a capacitor, is the charge on one of the plates, divided by the potential difference between them, as follows:
- At the same time, we can show (applying Gauss' Law to the surface of one of the plates), that the capacitance of a parallel-plate capacitor (with a dielectric of air), can be written as follows:
C = ε₀*A / d (2)
- If the space between plates, is filled with a dielectric of dielectric constant κ, the above equation becomes:
- If the capacitor, once charged, is disconnected from the battery, charge must keep the same.
- Now, if we remove the dielectric, as stated in (3) and (2), the capacitance C will decrease when removing the dielectric.
- From (1) if C decreases, and Q remains constant, in order to keep both sides of the equation equal each other, V (the potential difference between plates), must increase.
Answer:
v = 31.3 m / s
Explanation:
The law of the conservation of stable energy that if there are no frictional forces mechanical energy is conserved throughout the point.
Let's look for mechanical energy at two points, the highest where the body is at rest and the lowest where at the bottom of the plane
Highest point
Em₀ = U = m g y
Lowest point
= K = ½ m v²
As there is no friction, mechanical energy is conserved
Em₀ =
m g y = ½ m v²
v = √ 2 g y
Where we can use trigonometry to find and
sin 30 = y / L
y = L sin 30
Let's replace
v = RA (2 g L sin 30)
Let's calculate
v = RA (2 9.8 100.0 sin30)
v = 31.3 m / s