Answer:
What is the probability that a randomly selected family owns a cat? 34%
What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat? 82.4%
Step-by-step explanation: We can use a Venn (attached) diagram to describe this situation:
Imagine a community of 100 families (we can assum a number, because in the end, it does not matter)
So, 30% of the families own a dog = .30*100 = 30
20% of the families that own a dog also own a cat = 0.2*30 = 6
34% of all the families own a cat = 0.34*100 = 34
Dogs and cats: 6
Only dogs: 30 - 6 = 24
Only cats: 34 - 6 = 28
Not cat and dogs: 24+6+28 = 58; 100 - 58 = 42
What is the probability that a randomly selected family owns a cat?
34/100 = 34%
What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat?
A = doesn't own a dog
B = owns a cat
P(A|B) = P(A∩B)/P(B) = 28/34 = 82.4%
Answer:
B.x= -4 and E. x= 10 are the answers
Answer:
y = 14
Step-by-step explanation:
First find the slope of the line. To find the slope of the line, use the slope formula:

The slope of the line is 2.
Repeat this same process instead with points (1,4) and (6,y). Substitute m = 2.

So y = 14.
Answer:
0.3, 45%, 13/25
Step-by-step explanation:
Is the smallest to largest
The correct answer to the question that is being asked and presented above would be 'composite'. If there are two or more basic geometric figures combined, they form what is called a 'composite' figure.