All categories

3 years ago

Are the eight valence electrons the most stable configuration?

Chemistry

2 answers:

alina1380 [7]3 years ago

5 0

Answer: No, the noble gases are

Explanation:

Annette [7]3 years ago

3 0

Answer:

The most stable electron configuration is that of a noble gas, due to the fact that its valence shell is filled. For helium, that means two valence electrons (a duet) in the 1s sublevel, and for the rest it means eight valence electrons (an octet) in the outermost s and p sublevels.

You might be interested in

9. To become like a noble gas the element P will have a charge of

MrRa [10]

Answer:

to become a noble gas element P will have 2 electrons in it's outer most energy level if it has one energy level

and eight in the last energy level if more than one

6 0

3 years ago

What is the mass, in grams, 200mL of liquid with a density of 1.4g/mL

Tcecarenko [31]

The mass of the liquid is 280 g.

Mass = 200 mL × (1.4 g/1 mL) = 280 g

6 0

3 years ago

A 10-liter container has 2 moles of oxygen at a pressure of 92 kpa. The effective speed (rms) of the oxygen molecules in the gas

bezimeni [28]

The effective speed (rms) of the oxygen gas is 293.68 m/s.

<h3></h3><h3>What is Root-mean-square velocity?</h3>

Root mean square velocity is the square root of the mean of squares of the velocity of individual gas molecules

$v_{rms}=\sqrt[]{\frac{3RT}{M} }$

<em>where </em>R = universal gas constant

M = molar mass of the gas in kg/mol

T = temperature in Kelvin

According to the ideal gas law,

PV = nRT

RT = $\frac{PV}{n}$

Substitute in the rms velocity formula,

$v_{rms} = \sqrt[]{\frac{3PV}{nM} }$

P = 92 kPa, V = 10 L, n = 2 moles and M = 32 x 10⁻³ kg/mol

$v_{rms} = \sqrt[]{\frac{3\times92\times10}{2\times32\times10^-^3} }$

=293.68 m/s

Thus, the effective speed (rms) of O₂ gas is 293.68 m/s.

Learn more about Root-mean-square velocity:

brainly.com/question/15995507

#SPJ4

4 0

1 year ago

When atoms combine, the force of attraction that holds them together is a(

ziro4ka [17]

Electrostatic, meaning the attraction from one's positive nucleus is to the negative electrons of the other atom and vis versa.

3 0

4 years ago

Liquid hexane

maks197457 [2]

<u>Answer:</u> The mass of $H_2O$ produced is 2.52 g

<u>Explanation:</u>

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(1)

<u>For hexane:</u>

Given mass of hexane = 1.72 g

Molar mass of hexane = 86.18 g/mol

Putting values in equation 1, we get:

$\text{Moles of hexane}=\frac{1.72g}{86.18g/mol}=0.020mol$

<u>For oxygen gas:</u>

Given mass of oxygen gas = 8.0 g

Molar mass of oxygen gas= 32 g/mol

Putting values in equation 1, we get:

$\text{Moles of water}=\frac{8.0g}{32g/mol}=0.25mol$

The chemical equation for the combustion of hexane follows:

$2C_6H_{14}+19O_2\rightarrow 12CO_2+14H_2O$

By stoichiometry of the reaction:

If 2 moles of hexane reacts with 19 moles of oxygen gas

So, 0.020 moles of hexane will react with = $\frac{19}{2}\times 0.020=0.19mol$ of oxygen gas

As the given amount of oxygen gas is more than the required amount. Thus, it is present in excess and is considered as an excess reagent.

Thus, hexane is considered a limiting reagent because it limits the formation of the product.

By the stoichiometry of the reaction:

If 2 moles of hexane produces 14 moles of $H_2O$

So, 0.020 moles of hexane will produce = $\frac{14}{2}\times 0.020=0.14mol$ of $H_2O$

We know, molar mass of $H_2O$ = 18 g/mol

Putting values in above equation, we get:

$\text{Mass of }H_2O=(0.14mol\times 18g/mol)=2.52g$

Hence, the mass of $H_2O$ produced is 2.52 g

4 0

4 years ago

Are the eight valence electrons the most stable configuration?​

Are the eight valence electrons the most stable configuration?