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Arlecino [84]
3 years ago
8

how many grams of oxygen gas are needed to produce 10.0 grams of carbon dioxide according to the balanced equation of CH4

Chemistry
1 answer:
Alinara [238K]3 years ago
7 0
Molar mass of :

O2 = 16 * 2 = 32 g/mol

CO2 = 12 + 16 * 2 = 44 g/mol

<span>Balanced chemical equation :
</span>
1 CH4 + 2 O2 = 1 CO2 + 2 H2O
               ↓              ↓
             2 moles     1 mole

2* 32 g O2 ----------> 1* 44 g CO2
     x g O2 ------------> 10.0 g CO2

44 x = 2 * 32*10.0

44 x = 640

x =  \frac{640}{44}

x = 14.54 g of O2





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Explanation :

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(2) H_2SO_3(aq)\rightleftharpoons 2H^+(aq)+SO_3^{2-}(aq)         K_{c_2}=1.1\times 10^{-9}

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2HNO_2(aq)+SO_3^{2-}(aq)\rightleftharpoons H_2SO_3(aq)+2NO_2^-(aq)         K_{c}=?

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K_c=\frac{(K_{c_1})^2}{K_{c_2}}

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K_c=\frac{(4.5\times 10^{-4})^2}{1.1\times 10^{-9}}=184.09

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