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balandron [24]
3 years ago
7

Belinda git 18 out of 20 correct on a science test what percent of the questions did Belinda get correct

Mathematics
2 answers:
sveta [45]3 years ago
4 0
92% of the questions were correct.
Margarita [4]3 years ago
4 0
Expressed as a percentage, 18/20x100=90 percent
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Theresa has $12 in nickels and quarters. If she has the same number of each kind of coin, how many nickels and quarters does she
postnew [5]

Answer: She has 40 nickels and 40 quarters .

Step-by-step explanation:

Let be "n" the number of nickels Theresa has and "q" the number of quarters Theresa has.

You know that she has a total of $12 in nickels and quarters. In cents, this is:

\$12*100=1,200\ cents

Then, based on this you can write the following expression:

5n+25q=1,200

Since n=q, you can rewrite it as:

5n+25n=1,200

Solving for "n", you get:

30n=1,200\\\\n=\frac{1,200}{30}\\\\n=40

Therefore she has 40 nickels and 40 quarters .

7 0
3 years ago
Find the area of the parallelogram. Please this is due today. Thank you.
scZoUnD [109]
894 mi^2

as 24 x 37.25 = 894
4 0
3 years ago
CAN SOMEONE PLEASE ANSWER THISS ASAP PLEASE
solong [7]

Answer:

Step-by-step explanation:

11.04 = 10(1.02)^n

1.104 = 1.02^n

ln 1.104 = ln 1.02^n

ln 1.104 = n ln 1.02

n = ln 1.104/ ln 1.02

n = 4.99630409516

4.99 can be rounded to 5.

So a reasonable domain would be 0 ≤ x < 5

PART B)

f(0) = 10(1.02)^0

f(0) = 10(1)

f(0) = 10

The y-intercept represents the height of the plant when they began the experiment.

f(1) = 10(1.02)^1

f(1) = 10(1.02)

f(1) = 10.2

(1, 10.2)

f(5) = 10(1.02)^5

f(5) = 10(1.1040808)

f(5) = 11.040808

f(1)=10(1.02)^1

f(1)=10.2

Average rate= (fn2-fn1)/(n2-n1)

                     =11.04-10.2/(5-1)

                    =0.22

the average rate of change of the function f(n) from n = 1 to n = 5 is 0.22.  

8 0
2 years ago
5
natka813 [3]

Answer:

21s+8=r

need more characters

6 0
3 years ago
LIEDUMICIS.ISLIULIULUI marks 4 1 point → An archer shoots an arrow into the air. The equation that describes the path of the arr
elena55 [62]

4)

the arrow touches the ground when the heigth is 0

so we need to replace h=0 and solve for t

\begin{gathered} h=17t-5t^2 \\ 0=17t-5t^2 \\ 0=t(17-5t) \\ 0=17-5t \\ 5t=17 \\ t=\frac{17}{5}=3.4 \end{gathered}

<em>the arrow tuches the ground at 3.4 seconds</em>

5)

F=m\times a

replacing

185=m\times13.7

<em>solve for m</em>

\begin{gathered} m=\frac{185}{13.7} \\  \\ m=13.50 \end{gathered}

<em>the mass is 13.50Kg</em>

<em />

4 0
1 year ago
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