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4 years ago

Please give me the explanation so I KNOW that it's right? Thanks.

Mathematics

1 answer:

MrMuchimi4 years ago

5 0

Answer:

its A, B, C or D

Step-by-step explanation:

it has to be one of them.

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Find the slope Y=5x+12

NikAS [45]

Answer: The slope = 5.

Step-by-step explanation:

The equation of a line in the slope -intercept form is given by :-

$y=mx+c$

,where m= slope , c= y-intercept.

The slope of a line represents the rate of change of y with respect to x.

Given: Equation of line : Y= 5x+12

Here Slope (m)=5

Hence, the slope = 5.

6 0

3 years ago

Please help. I am doing a test and I do not understand what I am being asked.

Oksanka [162]

Answer:

one

Step-by-step explanation:

i have no idea what kind of test ur taking my guy but have fun

5 0

3 years ago

What is k in this proportional relationship?

Zolol [24]

Answer:

Step-by-step explanation:

K is the constant of proportionality or unit rate

(x, y)

(0, 0)

(2, 120)

(3, 180)

(4, 240)

120/2=60

180/2=60

240/2=60

The constant of proportionality or unit rate is 60

7 0

3 years ago

Read 2 more answers

Complete the table and write the equation for the relationship shown in the graph.

SVEN [57.7K]

8 = 1. The relationship equation is y = x - 7

4 0

4 years ago

The first term of a geometric sequence is 15, and the 5th term of the sequence is <img src="https://tex.z-dn.net/?f=%5Cfrac%7B24

sladkih [1.3K]

The geometric sequence is $15,9,\frac{27}{5},\frac{81}{25}, \frac{243}{125}$

Explanation:

Given that the first term of the geometric sequence is 15

The fifth term of the sequence is $\frac{243}{125}$

We need to find the 2nd, 3rd and 4th term of the geometric sequence.

To find these terms, we need to know the common difference.

The common difference can be determined using the formula,

$a_n=a_1(r)^{n-1}$

where $a_1=15$ and $a_5=\frac{243}{125}$

For $n=5$ , we have,

$\frac{243}{125}=15(r)^4$

Simplifying, we have,

$r=\frac{3}{5}$

Thus, the common difference is $r=\frac{3}{5}$

Now, we shall find the 2nd, 3rd and 4th terms by substituting $n=2,3,4$ in the formula $a_n=a_1(r)^{n-1}$

For $n=2$

$a_2=15(\frac{3}{5} )^{1}$

$=9$

Thus, the 2nd term of the sequence is 9

For $n=3$ , we have,

$a_3=15(\frac{3}{5} )^{2}$

$=15(\frac{9}{25} )$

$=\frac{27}{5}$

Thus, the 3rd term of the sequence is $\frac{27}{5}$

For $n=4$ , we have,

$a_4=15(\frac{3}{5} )^{3}$

$=15(\frac{27}{25} )$

$=\frac{81}{25}$

Thus, the 4th term of the sequence is $\frac{81}{25}$

Therefore, the geometric sequence is $15,9,\frac{27}{5},\frac{81}{25}, \frac{243}{125}$

5 0

3 years ago