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3 years ago

How you could use a number line to determine which of two numbers is greater

1 answer:

7 0

First of all because if it is negative it'll go left on the number line positive number s which are greater go to the right.

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What fraction, decimal or percent. Is equivalent to 9/9

8_murik_8 [283]

Answer:

1/1

1.0

100%

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Alex bikes 2 3/4 miles. Then, she runs 1 2/4 miles. The distance she bikes is how many times the distance she runs?

anastassius [24]

Answer:

The distance she bikes is 11/6 times as much as the distance she runs.

Step-by-step explanation:

Alex bikes 2.75 miles, runs 1.5 miles. The distance she bikes is 2.75/1.5 times as much as the distance she runs.

The distance she bikes is 11/6 times as much as the distance she runs.

7 0

3 years ago

Read 2 more answers

What are two ratios equvilant to 8:6?

disa [49]

4:3 (simplified) and 16:12 (doubled) both work
Hope this helps!

8 0

3 years ago

(a) Find the equation of the normal to the hyperbola x = 4t, y = 4/t at the point (8,2).

gtnhenbr [62]

The slope of the tangent line to the curve at (8, 2) is given by the derivative $\frac{dy}{dx}$ at that point. By the chain rule,

$\dfrac{dy}{dx} = \dfrac{dy}{dt} \times \dfrac{dt}{dx} = \dfrac{\frac{dy}{dt}}{\frac{dx}{dt}}$

Differentiate the given parametric equations with respect to $t$ :

$x = 4t \implies \dfrac{dx}{dt} = 4$

$y = \dfrac4t \implies \dfrac{dy}{dt} = -\dfrac4{t^2}$

Then

$\dfrac{dy}{dx} = \dfrac{-\frac4{t^2}}4 = -\dfrac1{t^2}$

We have $x=8$ and $y=2$ when $t=2$ , so the slope at the given point is $\frac{dy}{dx} = -\frac14$ .

The normal line to the same point is perpendicular to the tangent line, so its slope is +4. Then using the point-slope formula for a line, the normal line has equation

$y - 2 = 4 (x - 8) \implies \boxed{y = 4x - 30}$

Alternatively, we can eliminate the parameter and express $y$ explicitly in terms of $x$ :

$x = 4t \implies t = \dfrac x4 \implies y = \dfrac4t = \dfrac4{\frac x4} = \dfrac{16}x$

Then the slope of the tangent line is

$\dfrac{dy}{dx} = -\dfrac{16}{x^2}$

At $x = 8$ , the slope is again $-\frac{16}{64}=-\frac14$ , so the normal has slope +4, and so on.

5 0

2 years ago

Whats the length of CD?

Svet_ta [14]

Answer:

The answer of the question is 4.7

8 0

3 years ago