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2 years ago

15

Write "six times 3 minus 3" as an expression.

2 answers:

777dan777 [17]2 years ago

6 0

Answer:

6(3)-3

Step-by-step explanation:

serg [7]2 years ago

6 0

Answer:

Step-by-step explanation:

6x(−3)

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in the circl below, AD is diameter and AB is tangent at A. Suppose mADC=228*, find the measures of mCAB and mCAD. Type your nume

Andrew [12]

Given:

AD is diameter of the circle, AB is the tangent, and measure of arc ADC is 228 degrees.

To find:

The $m\angle CAB$ and $m\angle CAD$ .

Solution:

AD is diameter of the circle. So, the measure of arc AD is 180 degrees.

$m(arcADC)=m(arcAD)+m(arcDC)$

$228^\circ=180^\circ+m(arcDC)$

$228^\circ-180^\circ+=m(arcDC)$

$48^\circ+=m(arcDC)$

The measure inscribed angle is half of the corresponding subtended arc.

$m\angle CAD=\dfrac{1}{2}\times m(arcDC)$

$m\angle CAD=\dfrac{1}{2}\times 48^\circ$

$m\angle CAD=24^\circ$

AB is the tangent. So, $m\angle BAD=90^\circ$ because radius is perpendicular on the tangent and the point of tangency.

$m\angle BAD=m\angle CAB+m\angle CAD$

$90^\circ=m\angle CAB+24^\circ$

$90^\circ -24^\circ=m\angle CAB$

$66^\circ=m\angle CAB$

Therefore, $m\angle CAB=66^\circ$ and $m\angle CAD=24^\circ$ .

4 0

2 years ago

Could I get the difference of the meaning?

____ [38]

Absolute value of -3 is three, and then it just regular -3 equals -3 so basically whenever you see at -3 in those brackets or any negative number it means absolute value which will always be it’s positive version That negative number

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2 years ago

Write a fact with the same sum as 7+5

Hunter-Best [27]

12 = 7+5 Hope this helps:)

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3 years ago

The table shows a proportional relationship.

ra1l [238]

Y equal 1.4 to amke 1 x

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3 years ago

X^2+1/2x+____=2 + ____

natali 33 [55]

Answer: $x^2+\frac{1}{2}x+\frac{1}{16}=2 +\frac{1}{16}$

Step-by-step explanation:

Given the following Quadratic equation:

$x^2+\frac{1}{2}x=2 +$

You can change its formed by Completing the square.

In order to do Complete the square, you can follow these steps:

1. You can identify that:

$b=\frac{1}{2}$

2. Then, you can find $(\frac{b}{2})^2$ . This is:

$(\frac{\frac{1}{2}}{2})^2=(\frac{1}{4})^2=\frac{1}{16}$

3. Now you must add $\frac{1}{16}$ to both sides of the Quadratic equation in order to keep the balance. Then:

$x^2+\frac{1}{2}x+\frac{1}{16}=2 +\frac{1}{16}$

4. Finally, simplifying by actoring and adding the like terms, you get:

$(x+\frac{1}{4})^2=\frac{9}{4}$

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2 years ago