Answer:
0. vmhhdhgxhhffgvghcg8tygodull6yvylylf
With replacement, probability of selecting a good bulb remains
(63-9)/63
=6/7
If the bulbs are selected WITH replacement three times, then
P(all good)
= (6/7)^3 (by the multiplication rule)
= 216/343
= 0.630 (to three decimal places)
Wouldn’t it be 7*4/2? so the answer would be 14
Well first off if you have a negative sign in front of the seven, DO NOT have a plus sign because it will be confusing. So y-7=13? , You add 7 to 13 and = 20, so y= 20
