The height of the cone is inches, if the cylinder and cone have the same volume.The cylinder has a radius of 2 inches and a height of 3 inches. The cone has a radius of 3 inches.
Step-by-step explanation:
The given is,
A cylinder and a cone have the same volume
Cylinder has a radius 2 inches and height of 3 inches.
Cone has a radius of 3 inches
Step:1
For Cylinder'
Formula to calculate the volume of cylinder is,
..................................................(1)
where,
r - 2 inches
h - 3 inches
From the equation (1)
=
×
× 3
= 37.70
V = 37.70 cubic inches
Step:2
For cone,
Formula to calculate the volume of cone is,
..................................................(2)
From the statement,
cylinder and a cone have the same volume
= 
37.70 =
×
× 
37.70 = 9.42478 × h
Height of the cone, h = 4 inches
Result:
Thus the height of the cone is 4 inches, if a cylinder and cone have the same volume.The cylinder has a radius of 2 inches and a height of 3 inches. The cone has a radius of 3 inches.
Answer:
8 3/56
Step-by-step explanation:
8 whole number, 3 over 56
Well assuming that this would be a typical triangle, and not a right angle one, knowing that the sum of all sides adds up to 180 degrees, simply add all of the expressions and one value and make it equal to 180, and then solve for x.
(6x-1) + (X+14) + 20 = 180
6x - 1 + X + 14 = 160
7x - 1 + 14 = 160
7x + 13 = 160
7x = 147
X = 21.
Now solve for the angles by plugging in X.
A = 6x - 1 = 6(21) - 1 = 125 degrees
C = X + 14 = (21) + 14 = 35 degrees.
I believe these are the solutions.
The US equivalent of "liters to meters" would be something like
"quarts to yards", which is equally meaningless.
Liters and meters don't even measure the same thing. Liters describe
volume, whereas meters describe length or distance. They don't convert
to each other .
If volume units could be converted to length units, then you (or somebody
with a slightly better grasp of his math) would be able to figure out how many
inches of gas he put into his car last week, and the cost of a foot of milk.