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Scilla [17]
4 years ago
12

To create an entry code, you must first choose 2 letters and then 2 single digit numbers. How many entry codes can you create?

Mathematics
1 answer:
ivann1987 [24]4 years ago
3 0

Answer:

55600

Step-by-step explanation:

First times the number of possibilities of the amount of letters it could be so 26X26 as it is a non consecutive possibility that means both letters have the possibility to be the same. Then take the product of 26X26 and multiply it by the possibilities of the first number which is 10 then repeat that by again multiplying the product by 10 to represent the number of possibilities for the second number

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a tennis ball machine serves a ball vertically into the air from a height of 2 feet, with an inital speed of 120 feet per second
balu736 [363]
Check the picture below.

\bf ~~~~~~\textit{initial velocity}\\\\
\begin{array}{llll}
~~~~~~\textit{in feet}\\\\
h(t) = -16t^2+v_ot+h_o \\\\
\end{array} 
\quad 
\begin{cases}
v_o=\stackrel{\textit{initial velocity of the object}}{120}\\\\
h_o=\stackrel{\textit{initial height of the object}}{2}\\\\
h=\stackrel{}{\textit{height of the object at "t" seconds}}
\end{cases}
\\\\\\
h(t)=-16t^2+120t+2

 \bf \textit{ vertex of a vertical parabola, using coefficients}\\\\
\begin{array}{llll}
h(t)= &{{ -16}}t^2&{{ +120}}t&{{ +2}}\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}\qquad 
\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad  {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)
\\\\\\
\left(-\cfrac{120}{2(-16)}~~,~~2-\cfrac{120^2}{4(-16)}  \right)\implies \left( \cfrac{15}{4}~~,~~2+\cfrac{14400}{32} \right)

\bf \left( \cfrac{15}{4}~~,~~2+450 \right)\implies \left( \stackrel{seconds}{3\frac{3}{4}}~~,~~\stackrel{feet}{452} \right)

7 0
3 years ago
I need help with this problem:(​
steposvetlana [31]

Answer:

8

Step-by-step explanation:

According to Euclidean theorem

m^2 = 4×16

m^2 = 64

m = 8

3 0
3 years ago
If 12 is replaced with 3 in the following set what will happen with the value of the range 28,45,12,34,36,45,19,20
nordsb [41]

Answer:

The interquartile range remains the same.

Step-by-step explanation:

Interquartile range is the difference between first and third quartile.

I.Q.R.=Q_3-Q_1

The given data is

28, 45, 12, 34, 36, 45, 19, 20

Arrange the data is ascending order.

12, 19, 20, 28, 34, 36, 45, 45

(12, 19, 20, 28), (34, 36, 45, 45)

(12, 19), (20, 28), (34, 36), (45, 45)

The first quartile is midpoint of 19 and 20 and the third quartile is the midpoint of 36 and 45.

Q_1=\frac{19+20}{2}=19.5

Q_3=\frac{36+45}{2}=40.5

I.Q.R.=Q_3-Q_1

I.Q.R.=40.5-19.5=21

The interquartile range of given data is 21.

If 12 is replaced with 3 in the following set, then the given data is

3, 19, 20, 28, 34, 36, 45, 45

(3, 19, 20, 28), (34, 36, 45, 45)

(3, 19), (20, 28), (34, 36), (45, 45)

The first quartile is midpoint of 19 and 20 and the third quartile is the midpoint of 36 and 45.

Q_1=\frac{19+20}{2}=19.5

Q_3=\frac{36+45}{2}=40.5

I.Q.R.=Q_3-Q_1

I.Q.R.=40.5-19.5=21

The interquartile range of given data is 21.

The interquartile range remains the same. Therfore option 3 is correct

8 0
3 years ago
Read 2 more answers
-5x+5y=10<br> 3x-3y= -10
strojnjashka [21]

Answer:

ummmm math?

Step-by-step explanation:

7 0
3 years ago
How can I solve this quadratic using the square root properly?
Citrus2011 [14]

Answer:

x = <u>+</u>3

Step-by-step explanation:

4x² = 36

sqareroot both side we get,

√4x² = √36

2x = 6

x = 6/2

x = <u>+</u>3

Thus, The answer is <u>+</u>3

<u>-TheUnknown</u><u>S</u><u>cientist</u>

7 0
3 years ago
Read 2 more answers
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