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3 years ago

What is the r value of the following geometric sequence? 2, 6, 18, 54,...

1 answer:

5 0

162 is the next in the sequence. It's a sequential value. Just multiply the previous number by 3, and you have you answer.

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Mr. Cooper ask his students whether they prefer to go to the aquarium or the planetarium for a field trip. The table shows the r

nirvana33 [79]

Could you give some information? The table would be really good, I’d be able to help you more efficiently. ☺️

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3 years ago

State the range of the graph and explain what the graph represents.

Eva8 [605]

Answer:

The range of the graph is [-10, 10]

Step-by-step explanation:

This represents how the y-values of the graph range from -10 to 10.

Because there are no arrow marks on the ends of the graph, we know that the graph stops there at -10 and 10 and doesn't go beyond that.

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2 years ago

How to do a do and undo chart for 3s=k(b+c)

katen-ka-za [31]

Answer:5

Step-by-step explanation:

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3 years ago

Solve the following: 2(5x-3)

Otrada [13]

Answer:

The vale of x is 3/5.

Step-by-step explanation:

First you have to expand out :

$2(5x - 3)$

$= 2(5x) - 2(3)$

$= 10x - 6$

Next you have to solve it by adding 6 to both sides :

Let expression = 0,

$10x - 6 = 0$

$10x - 6 + 6 = 0 + 6$

$10x = 6$

$x = \frac{6}{10}$

$x = \frac{3}{5}$

6 0

2 years ago

Read 2 more answers

An investor in Apple is worried the latest management earnings forecast is too aggressive and the company will fall short. His f

Inga [223]

Answer:

$P(GoodR/Below Forecast)= \frac{P(GoodR n Below Forecast)}{P(Below Forecast)}= \frac{0.02}{0.49} = 0.04$

Step-by-step explanation:

Hello!

Given the probability information about analyst's report (Good, Medium, and Bad) and the earnings announcement (Forecast), you have to calculate the probability that the analyst issued a good report, given that the earnings announcement was "bellow the forecast".

Symbolically: P(Good Report/Below Forecast)

This is a conditional probability, a little reminder:

If you have the events A and B, that are not independent, the probability of A given that B has already happened can be calculated as:

$P(A/B)= \frac{P(AnB)}{P(B)}$

Where P(A∩B) is the intersection between the two events and P(B) represents the marginal probability of ocurrence of B.

*-*

Using that formula:

$P(Good Report/Below Forecast)= \frac{P(Good Report n Below Forecast)}{P(Below Forecast)}$

As you can see you have to calculate the value of the probability for the intersection between "Good report" and "Below Forecast" and the probability for P(Below Forecast)

Using the given probability values you can clear the value of the intersection:

$P(BelowForecast/Good Report)= \frac{P(Good Report n Below Forecast)}{P(Good Report)}$

P(Good Report ∩ Below Forecast)= P(BelowForecast/GoodReport)*P(Good Report)= 0.1*0.2= 0.02

Now the probability of an earnings announcement being "Below Forecast" is marginal, that is if you were to arrange all possible outcomes in a contingency table this probability will be in the marginal sides of the table:

Below Forecast

Good Report P(GoodR∩BelowF)

Medium Report P(MediumR∩BelowF)

Bad Report P(BadR∩BelowF)

Total P(Below Forecast)

Then P(BelowF)=P(GoodR∩BelowF)+P(MediumR∩BelowF)+P(BadR∩BelowF)

You can clear the two missing probabilities from the remaining information:

$P(BelowForecast/MediumR)= \frac{P(BelowForecast n MediumR}{P(MediumR)}$

P(BelowF∩MediumR)= P(BelowF/MediumR)*P(MediumR)= 0.4*0.5= 0.2

$P(BelowForecast/BadR)= \frac{P(BelowForecastnBadR)}{P(BadR)}$

P(BelowF∩BadR)= P(BelowF/BadR)*P(BadR)= 0.9*0.3= 0.27

Now you can calculate the probability of the earning announcement being below forecast:

P(BelowF)=P(GoodR∩BelowF)+P(MediumR∩BelowF)+P(BadR∩BelowF)

P(BelowF)= 0.02+0.2+0.27= 0.49

And finally the asked probability is:

$P(GoodR/Below Forecast)= \frac{P(GoodR n Below Forecast)}{P(Below Forecast)}= \frac{0.02}{0.49} = 0.04$

I hope this helps!

3 0

2 years ago