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KATRIN_1 [288]
3 years ago
12

What are the abbreviations for a milliliter, a megameter, and a centigram, respectively?

Mathematics
2 answers:
Sliva [168]3 years ago
8 0

Step-by-step explanation:

In this question, we need to write the abbreviations for a milliliter, a megameter and a centimeter. Firstly, we will see the conversion formula from one unit to another.

1 milliliter = 0.001 liters

1\ megameter = 10^6\ m

and

1 centigram = 0.01 grams

The abbreviations for these quantities are as follows :

Milliliter = mL

Megameter = Mm

Centigram = cg

Hence, this is the required solution.

babunello [35]3 years ago
7 0
The answer that you are looking for is, ml, Mm, cg
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The calibration of a scale is to be checked by weighing a 13 kg test specimen 25 times. Suppose that the results of different we
Natali5045456 [20]

Solution :

a).

Given : Number of times, n = 25

            Sigma, σ = 0.200 kg

            Weight, μ = 13 kg

Therefore the hypothesis should be tested are :

$H_0 : \mu = 13 $

$H_a : \mu \neq 13$

b). When the value of $\overline x = 12.84$

 Test statics :

   $Z=\frac{(\overline x - \mu)}{\frac{\sigma}{\sqrt n}} $

  $Z=\frac{(14.82-13)}{\frac{0.2}{\sqrt {25}}} $

          $=\frac{1.82}{0.04}$

          = 45.5  

P-value = 2 x P(Z > 45.5)

            = 2 x 1 -P (Z < 45.5) = 0

Reject the null hypothesis if P value  < α = 0.01 level of significance.

So reject the null hypothesis.

Therefore, we conclude that the true mean measured weight differs from 13 kg.

3 0
3 years ago
Help for brianilist please!!!
Dima020 [189]
Hi there!!!

So using this rule:

Area = base * height
20ft  * 15ft  = 300ft^2
↑            ↑
base    height      

HOPE IT HELPS U!!!!!!!!!
THE ANSWER IS 300 FT^2

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5 0
4 years ago
Emir is standing in a treehouse and looking down at a swingset in the yard next door. The angle of depression from Emir's eyelin
boyakko [2]
<h3>Answer:  24 feet  (Choice D)</h3>

=============================================

Explanation:

Refer to the diagram below. The goal is to find x, which is the horizontal distance from the base of the tree to the swing set.

Focus on triangle BCD.

The angle B is roughly 30.26 degrees, and this is the angle of depression. This is the amount of degrees Emir must look down (when starting at the horizontal) to spot the swing set.

We know that he's 14 ft off the ground, which explains why AB = CD = 14.

The goal is to find BC = AD = x.

---------------------------

Again, keep your focus on triangle BCD.

We'll use the tangent ratio to say

tan(angle) = opposite/adjacent

tan(B) = CD/BC

tan(30.26) = 14/x

x*tan(30.26) = 14

x = 14/tan(30.26)

x = 23.9965714046732

That value is approximate. Make sure your calculator is in degree mode.

That value rounds to 24 feet when rounding to the nearest whole foot.

6 0
3 years ago
In parallelogram JKLM, m&lt;L exceeds m&lt;M by 30 degrees. What is the measure of M&lt;J?
Damm [24]

 

Answer:

2)105°

Step-by-step explanation:

In this parallelogram, J should be congruent to L (J=L). We can solve this problem if we find out the value of L.

The sum of the adjacent angle of the parallelogram will be equal to 180 degrees, so  the equation is

L + M = 180

M=180- L

If L exceeds M by 30 degrees then the equation will be

L=M +30  

If you combine both equations, it will be

L+30 = M +30

L+30 = (180- L) +30

L + L= 180 + 30

2L= 210

L=105

3 0
4 years ago
Factor 2x2 + 7x + 3. <br> (2x + 2)(x + 1) <br> (2x + 3)(x + 1) (2x + 1)(x + 3)
maks197457 [2]
<h3>Answer:</h3>

(2x + 1)(x + 3)

<h3>Step-by-step explanation:</h3>

It is probably easier to try the answer choices than to try to factor the expression yourself.

(2x + 2)(x + 1) = 2x² +4x +2

(2x + 3)(x + 1) = 2x² +5x +3

(2x + 1)(x + 3) = 2x² +7x +3 . . . . . correct choice

_____

<em>Constructed solution</em>

If you want to factor this yourself, you can look for factors of "ac" that add to give "b". That is, you want factors of 2·3 = 6 that add up to give 7. You don't have to look very far.

... 6 = 1·6 = 2·3 . . . . . . the first factor pair adds to give 7

Now, rewrite the x term using the sum of these numbers.

... 2x² +(1 +6)x +3

... 2x +x +6x +3 . . . . eliminate parentheses

... (2x +x) +(6x +3) . . . . group pairs of terms

... x(2x +1) +3(2x +1) . . . . factor each pair

... (x +3)(2x +1) . . . . . . matches the last selection

6 0
3 years ago
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