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4 years ago

7

Nathan cell phone company charges a monthly rate of $12.95 and $.25 a minute per call the bill for X minutes is $21.21 write any

Quetion that models the situation

1 answer:

Natalija [7]4 years ago

4 0

The answers should be about 9 minutes and 2.4 seconds.

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Is 1/2(2p+9)=-p+5 a one solution or infinite solution or no solution

vitfil [10]

Your inequality has one solution which is p = 1/4

4 0

3 years ago

An educator claims that the average salary of substitute teachers in school districts is less than $60 per day. A random sample

valentina_108 [34]

Answer:

$t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626$

The degrees of freedom are given by:

$df=n-1=8-1=7$

The p value would be given by:

$p_v =P(t_{(7)}$

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

Step-by-step explanation:

Information given

60, 56, 60, 55, 70, 55, 60, and 55.

We can calculate the mean and deviation with these formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

Replacing we got:

$\bar X=58.875$ represent the mean

$s=5.083$ represent the sample standard deviation for the sample

$n=8$ sample size

$\mu_o =60$ represent the value that we want to test

$\alpha=0.1$ represent the significance level

t would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to test if the true mean is less than 60, the system of hypothesis would be:

Null hypothesis: $\mu \geq 60$

Alternative hypothesis: $\mu < 60$

The statistic would be given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info we got:

$t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626$

The degrees of freedom are given by:

$df=n-1=8-1=7$

The p value would be given by:

$p_v =P(t_{(7)}$

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

3 0

3 years ago

The problem of matching aircraft to passenger demand on each flight leg is called the flight assignment problem in the airline i

Darina [25.2K]

Answer:

Step-by-step explanation:

Given that the demand for the 6 p.m. flight from Toledo Express Airport to Chicago's O'Hare Airport on Cheapfare Airlines is normally distributed with a mean of 132 passengers and a standard deviation of 42

Let X be the no of passengers who report

X is N(132, 42)

Or Z is $\frac{x-132}{42}$

a) Suppose a Boeing 757 with a capacity of 183 passengers is assigned to this flight.

the probability that the demand will exceed the capacity of this airplane

= $P(X>183) = P(Z>1.21) =$

$=0.5-0.3869\\=0.1131$

b) the probability that the demand for this flight will be at least 80 passengers but no more than 200 passengers

= $P(80\leq x\leq 200)\\= P(-1.23\leq z\leq 1.62)\\$

=0.4474+0.3907

=0.8381

c) the probability that the demand for this flight will be less than 100 passengers

$=P(x$

d) If Cheapfare Airlines wants to limit the probability that this flight is overbooked to 3%, how much capacity should the airplane that is used for this flight have? passengers

= $P(Z>c)=0.03\\c=1.88\\X=132+1.88(42)\\=210.96$

e) 79th percentile of this distribution

= $132+0.81(42)\\= 166.02$

7 0

4 years ago

The population of city B was approximately 7,150,000 and it increased by 0.8% in one year.what is the new population

QveST [7]

Answer:

7,207,200

is the answer

4 0

3 years ago

Read 2 more answers

How many factors of 2 are there in 2³? answers> 1 2 3 5

algol [13]

Answer:

2

Step-by-step explanation:

2^3= 2*2*2

factors of 8= 1,2,4,8

factors of 2= 1,2

6 0

3 years ago