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3 years ago

How you guys solve these ?? multiplying and dividing complex??

Mathematics

1 answer:

Ostrovityanka [42]3 years ago

6 0

$i^2(2i^2-5)=-1(2(-1)-5)=-1*(-7)=7 \\ \\ i^2(3+i^2)=(-1)(3-1)=-1*2=-2 \\ \\ 
2i(2i-i^3)=2i^2(2-i^2)=-2(2+1)=-2*3=-6 \\ \\
 i(4i^3-i)=i^2(4i^2-1)=-1(-4-1)=5$

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Step-by-step explanation:

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