Question

at a checkers tournament there where 64 players. It was elimatation tournament. how many games where played before there was a winner

Answer 1

There are 64 players. For each group, one person is eliminated. You will divide 64/2(the # of people is 64, the number op people in each group is 2). You will get 32. 32 people are remaining. You will, again, divide. 32/2=16. 16 people remain. Divide, again by 2. 16/2=8. Divide by 2 again until you get to 1.

hope this helps!

Answer 2

So first game
half were eliminated
we notice a pattern
first game=64 times 1/2
next game 32 times 1/2 so

so just multiply by 1/2 till you get 1
round 1 64/2=32
round 2  32/2=16
round 3  16/2=8
round 4  8/2=4
round  5 4/2=2
round 6  2/2=1

6  is the answer