hi
1st draw: green
2/12. (2 green out of 12 marbles), reduces to 1/6
2nd draw: blue
4/11 (4 blue marbles out of the 11 marbles remaining after 1st draw.)
Probability of theses BOTH happening: multiply these individual probabilities.
Conditional probability:
P(a and b) = P(a)P(b|a)
Prob(event 1) × Prob(event 2 given event 1).
1/6 • 4/11 = 4/66 = 2/33 or 0.0606. just a hair over 6% probability of the described sequence hapening.
Answer:
This equation does have real solutions contrary to your question. They are 
OR 
.
Step-by-step explanation:
In order to prove this has real number solutions, we simply need to use the quadratic formula. To do this, we first need to solve for 0.
2x^2 + 18x = 10
2x^2 + 18x - 10 = 0
Now that we have this and they are all factors of 2, we can divide everything by 2 for ease.
2x^2 + 18x - 10 = 0
x^2 + 9x - 5 = 0
Now we can use the quadratic equation to solve. Remember that A = 1 due to the coefficient of x^2, B = 9 as the coefficient of x and C = -5 as the constant.
OR
Answer:
$4
Step-by-step explanation:
Because we know that Nancy bought a drink for 2 dollars, and we are just trying to find the cost of the candy bars, we can subtract 2 dollars from the drink from the total cost:
38 - 2 = 36
Now, the 9 candy bars cost 36 dollars, so to find the individual price of each candy bar, we divide 36 by 9:
36 / 9 = 4
So, each candy bar costs 4 dollars
Hope this helps :)
Answer:
acute
Step-by-step explanation:
