The relationship of distance-speed-time
distance = velocity × time
d = vt
Given:
v₁ = 35 mph
v₂ = 50 mph
the hypotenuse = 366
for example h is the time in hour
Solution:
d₁² + d₂² = (hypotenuse)²
(v₁t)² + (v₂t)² = 366²
(35h)² + (50h)² = 366²
1,225h² + 2,500h² = 133,956
3,725h² = 133,956
h² = 133,956 / 3,725
h² = 35.9613
h = 5.99
to the nearest hour ⇒ 6
The buses will be 366 miles apart in 6 hours
No it is not have a nice day/night
1 kilometer is 1000 meters. Therefore, 2 kilometers is 2000 meters. 2000 is greater than 3000, so Sally rode farther by 1000 meter, or 1 kilometer.
Answer:
h(t)=3/2t+59
h(t)=2/3(15)+64 h(t)=2/3(30)+64
74= 10+64 84=20+64
74=74 84=84
It can be 5, because 5 times -3 = -15