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Ira Lisetskai [31]
3 years ago
11

You plan to construct a brick wall measuring 15 ft. in length, 6 ft. high, and 1 ft. in width. If a brick measures 6 in. x 4 in.

x 2 in., how many bricks will you need? (Remember to round up.)
Mathematics
1 answer:
sertanlavr [38]3 years ago
3 0
Number of bricks = volume of wall/volume of 1 brick --------- (both in same units 
<span>volume of wall = (15 × 12)(6 × 12)(1 × 12) in³ -------- convert all in inches </span>
<span>volume of 1 brick = 6 × 4 × 2 in³ </span>

<span>Number of bricks = (15 × 12)(6 × 12)(1 × 12)/(6 × 4 × 2) </span>
<span>= (15 × 12)(6 × 3) </span>
<span>= 3240 </span>
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svetoff [14.1K]

Answer:

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Step-by-step explanation:

Given

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7 0
3 years ago
Two skateboarders, Ron and Bob, are traveling in opposite directions.Ton travels at 8 feet per second and bob travels at 10 feet
omeli [17]

Time taken before they are 2640 feet is 146.67 seconds

<em><u>Solution:</u></em>

The distance is given by formula:

distance = speed \times time

<em><u>Ton travels at 8 feet per second</u></em>

Let us assume, time taken = t

speed = 8 feet per second

Then, distance is given as:

Distance covered by Ton = 8t

<em><u>Bob travels at 10 feet per second</u></em>

Then, distance is given as:

Distance covered by Bob = 10t

How long will it take before they are 2640 feet

Which means,

Distance covered by Ton + Distance covered by Bob = 2640

8t + 10t = 2640\\\\18t = 2640\\\\Divide\ both\ sides\ of\ equation\ by\ 18\\\\t = 146.67

Thus time taken before they are 2640 feet is 146.67 seconds

<h3><u>Method 2:</u></h3>

Since trains are moving in opposite directions, their speeds must be added

speed = 8 + 10 = 18 feet per second

Given distance = 2640 feet

Therefore, time taken is:

time = \frac{distance}{speed}\\\\time = \frac{2640}{18} = 146.67 \text{ second }

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Step-by-step explanation:

Given

The attached figure

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Step-by-step explanation:

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6 0
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