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Hitman42 [59]
3 years ago
14

Anyone know the answer to 2 and 3

Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
7 0
2 is C and 3 is 24...................................
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Please help this was due today
Aleksandr [31]

Answer:

Why didn't u do it ?

Step-by-step explanation:

i know dumb question but i got points so i'm a OK if u were wondering

8 0
3 years ago
How many complex roots does the polynomial equation below have? x^5 - 3 = 0
const2013 [10]

For any polynomial equation, The Fundamental Theorem of Algebra tells you that the highest degree present will tell you how many complex roots the equation has. There are only two terms, "x^{5}" and "3". The x^{5} term has a degree of 5, its exponent. The 3 term has a degree of zero, because you could write it as 3 * x^{0} = 3 * 1 using the zero exponent rule.


The degrees present are 5 and 0. Choose the highest one, 5. So, the answer here is D.

8 0
3 years ago
Please help :) If you know anything about combining equations can you help me :)
julsineya [31]

Answer:

-5x - 8y = -5

Step-by-step explanation:

Whenever we two equations, we are essentially just adding the left sides up and then the right sides up. Here, let's write these into one whole big equation:

(4x - 4y) + (-9x - 4y) = -2 + (-3)

Taking the parentheses out, we have:

4x - 4y - 9x - 4y = -2 - 3

Combine like terms:

4x - 9x - 4y - 4y = -5

-5x - 8y = -5

Hope this helps!

5 0
3 years ago
Read 2 more answers
Katie can mow at a constant speed rate of 4/5 lawns per hour
andrey2020 [161]

Answer:

y=4/5x+B

what is the whole question?

8 0
3 years ago
A curve has the equation y = x^3 + 3x^2 − 16x + 2. a) Find an equation of the tangent to the curve at the point P (2, −10). Ive
Vesnalui [34]
The equation of the tangent to the curve at the point P(2, -10) is:
y = 8x - 26
f(x)=x^{3}+3x^{2}-16x
f'(x)=3x^{2}+6x-16
f'(2)=12+12-16=8
We need to find the coordinates of point Q where the slope of the tangent to the curve f(x) must also be 8.
f'(x)=3x^{2}+6x-16=8
Now we have a quadratic:
3x^{2}+6x-16-8=0
which simplifies to:
x^{2}+2x-8=0
which factorizes to:(x + 4)(x - 2) = 0
Therefore x = -4, 2.
f(-4) = 48
Therefore the coordinates of Q are (-4, 48).
3 0
3 years ago
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