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4 years ago

Helpppppppppppppppppppppppppppppp

Mathematics

1 answer:

Marta_Voda [28]4 years ago

8 0

Answer:

1) 90%

2)40%

3)75%

Step-by-step explanation:

the space between 2 lines are considered 10%. so let's take the first one for instance

1) as I said before, the space between 2 lines are considered 10%. So what you are going to use is the 10 times table (it will be a really helpful thing if you know all of the time table from 1 - 10) now what you do is count all the way from 0 till the blue thing ends. but If blue thing ends in the middle like in the picture number 3 then it's considered 5% since it's only halfway

I hope it was hopeful and that you understood

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Write 350 as a product of primes. Use index notation when giving your answer

Mkey [24]

Answer:

5² x 7 x 2

Step-by-step explanation:

350

= 35 x 10

= 7 x 5 x 5 x 2

= 5² x 7 x 2

8 0

3 years ago

The 6 term of a G.P is -2\27 and it's first term is 18.what is the common ratio

Airida [17]

Answer:

r = - $\frac{1}{3}$

Step-by-step explanation:

The n th term of a GP is

$a_{n}$ = a₁ $r^{n-1}$

where a₁ is the first term and r the common ratio

Here a₁ = 18 and a₆ = - $\frac{2}{27}$ , then

18 $r^{5}$ = - $\frac{2}{27}$ ( divide both sides by 18 )

$r^{5}$ = - $\frac{1}{243}$ ( take the fifth root of both sides )

r = $\sqrt[5]{-\frac{1}{243} }$ = - $\frac{1}{3}$

4 0

3 years ago

Differentiating a Logarithmic Function in Exercise, find the derivative of the function. See Examples 1, 2, 3, and 4.

Leni [432]

Answer: $\dfrac{2x^2-1}{x(x^2-1)}$

Step-by-step explanation:

The given function : $y=\ln(x(x^2 - 1)^{\frac{1}{2}})$

$\Rightarrow\ y=\ln x+\ln (x^2-1)^{\frac{1}{2}}$ [ $\because \ln(ab)=\ln a +\ln b$ ]

$\Rightarrow y=\ln x+\dfrac{1}{2}\ln (x^2-1)}$ [ $\because \ln(a)^n=n\ln a$ ]

Now , Differentiate both sides with respect to x , we will get

$\dfrac{dy}{dx}=\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})\dfrac{d}{dx}(x^2-1)$ (By Chain rule)

[Note : $\dfrac{d}{dx}(\ln x)=\dfrac{1}{x}$ ]

$\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})(2x-0)$

[ $\because \dfrac{d}{dx}(x^n)=nx^{n-1}$ ]

$=\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})(2x) = \dfrac{1}{x}+\dfrac{x}{x^2-1}\\\\\\=\dfrac{(x^2-1)+(x^2)}{x(x^2-1)}\\\\\\=\dfrac{2x^2-1}{x(x^2-1)}$

Hence, the derivative of the given function is $\dfrac{2x^2-1}{x(x^2-1)}$ .

8 0

4 years ago

I need help with # 14 and 15 ASAP... It is due tomorrow ..can some one please help me with it

Angelina_Jolie [31]

Answer:

See explanation

Step-by-step explanation:

A. Gasoline fill-up fee = $4.50

Cost per hour = $40

Average cost = C

Number of hours the scootcar is rented = h

Cost per h hours = $40h

Total cost = $40h + $4.50

Hence,

C = 40h+4.5

B. To plot the graph of the function, find h- and C- intercepts.

When h = 0, then C = 4.5, and we have point (0,4.5)

When C = 0, then 0 = 40h + 4.5, h = -45/400 = -0.1125, and we have point (-0.1125,0)

Plot these two points and connect them with a straight line.

Graph is attached, but you should take only that part of the graph that corresponds to points with h > 0, because the number of hours cannot be negative

8 0

4 years ago

(I NEED THIS ANSWERED QUICKLY! I WILL GIVE BRAINLIEST TO FIRST CORRECT ANSWER!)

dezoksy [38]

Answer:

Step-by-step explanation:

literlay just count

3 0

4 years ago