HELP ME, PLZ. 100 POINTS !!!

Mathematics

1 answer:

marta [7]2 years ago

3 0

Answer:

x=2√5/5

x=-2√5/5

Step-by-step explanation:

13√(2√5/5)^2-(2√5/5)^4+9√(2√5/5)^2+(2√5/5)^4=16

13√(4×5/25)-(16×25/625)+9√(4×5/25)+(16×25/625)

13√(4/5)-(16/25)+9√(4/5)+(16/25)

13√(4/25)+9√(36/25)

13×2/5+9×6/5

26/5+54/5

16=16 (proven)

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Whats 1-2x+3y for x=-2 and y=-5 ?

lawyer [7]

Answer:

-10

Step-by-step explanation:

2*-2=-4

3*-5=-15

1-(-4)+(-15)=-10

5 0

2 years ago

Earth is approximately 9.3 × 107 miles from the sun. Saturn is approximately 8.87 × 108 miles from the sun. About how much farth

Lostsunrise [7]

First you get both distances
9.3 x 107 = 995.1 miles
8.87 x 108 = 957.96 miles
then you subtract them both
995.1 - 957.96 = 37.14 miles
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5 0

3 years ago

explain how you can use a straightedge and a protractor to show that each angle you formed by a bisector is one-half the origina

Natasha2012 [34]

You can do that by simply measuring the main angle and then measuring each of the two angles. If you bisected the angle correctly, you will find that each of the two angles is equal to half the original.

You can measure the angle by following these steps:
1- Place the straightedge on the base of the angle.
2- Slide the protractor over it until the vertex of the angle is at the zero of the protractor.
3- Measure the angle.

3 0

3 years ago

Let g be the function given by g(x)=limh→0sin(x h)−sinxh. What is the instantaneous rate of change of g with respect to x at x=π

lorasvet [3.4K]

The instantaneous rate of change of g with respect to x at x = π/3 is 1/2.

<h3>How to determine the instantaneous rate of change of a given function</h3>

The instantaneous rate of change at a given value of $x$ can be found by concept of derivative, which is described below:

$g(x) = \lim_{h \to 0} \frac{f(x+h)-f(x)}{h}$

Where $h$ is the difference rate.

In this question we must find an expression for the instantaneous rate of change of $g$ if $f(x) = \sin x$ and evaluate the resulting expression for $x = \frac{\pi}{3}$ . Then, we have the following procedure below: