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3 years ago

The quotient of a number increased by 13 and -7 is -4

Mathematics

1 answer:

Ahat [919]3 years ago

7 0

Answer:

Step-by-step explanation:

Quotient is the number remained after divident is divided by divisor

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2 equivalent forms of 0.7875

nadezda [96]

Idk what that answer is soooo

4 0

3 years ago

In the diagram below,

mel-nik [20]

Answer:

<H = 40

Step-by-step explanation:

Complementary angles add to 90 degrees

2x+10 + x+20 = 90

Combine like terms

3x+30 = 90

Subtract 30

3x+30 -30 = 90-30

3x = 60

Divide by 3

3x/3 = 60/3

x = 20

<H = x+20 = 20+20 = 40

3 0

3 years ago

Pythagorean Theorem

Sindrei [870]

Pythagorean Theorem: a^2+b^2=c^2

Plug in values.

15^2+sqrt(207)^2=(12sqrt(3))^2
225+207=432
432=432

Yes, this is a right triangle.

3 0

4 years ago

Read 2 more answers

Solve the given initial-value problem. x' = 1 2 0 1 − 1 2 x, x(0) = 2 7

Ilia_Sergeevich [38]

I'll go out on a limb and guess the system is

$\mathbf x'=\begin{bmatrix}\frac12&0\\1&-\frac12\end{bmatrix}\mathbf x$

with initial condition $\mathbf x(0)=\begin{bmatrix}2&7\end{bmatrix}^\top$ . The coefficient matrix has eigenvalues $\lambda$ such that

$\begin{vmatrix}\frac12-\lambda&0\\1&-\frac12-\lambda\end{vmatrix}=\lambda^2-\dfrac14=0\implies\lambda=\pm\dfrac12$

The corresponding eigenvectors $\eta$ are such that

$\lambda=\dfrac12\implies\begin{bmatrix}\frac12-\frac12&0\\1&-\frac12-\frac12\end{bmatrix}\eta=\begin{bmatrix}0&0\\1&-1\end{bmatrix}\eta=\begin{bmatrix}0\\0\end{bmatrix}$
$\implies\eta=\begin{bmatrix}1\\1\end{bmatrix}$

$\lambda=-\dfrac12\implies\begin{bmatrix}\frac12+\frac12&0\\1&-\frac12+\frac12\end{bmatrix}\eta=\begin{bmatrix}1&0\\1&0\end{bmatrix}\eta=\begin{bmatrix}0\\0\end{bmatrix}$
$\implies\eta=\begin{bmatrix}0\\1\end{bmatrix}$

So the characteristic solution to the ODE system is

$\mathbf x(t)=C_1\begin{bmatrix}1\\1\end{bmatrix}e^{t/2}+C_2\begin{bmatrix}0\\1\end{bmatrix}e^{-t/2}$

When $t=0$ , we have

$\begin{bmatrix}2\\7\end{bmatrix}=C_1\begin{bmatrix}1\\1\end{bmatrix}+C_2\begin{bmatrix}0\\1\end{bmatrix}=\begin{bmatrix}C_1\\C_1+C_2\end{bmatrix}$

from which it follows that $C_1=2$ and $C_2=5$ , making the particular solution to the IVP

$\mathbf x(t)=2\begin{bmatrix}1\\1\end{bmatrix}e^{t/2}+5\begin{bmatrix}0\\1\end{bmatrix}e^{-t/2}$

$\mathbf x(t)=\begin{bmatrix}2e^{t/2}\\2e^{t/2}+5e^{-t/2}\end{bmatrix}$

5 0

4 years ago

Jennifer has $65 to spend on pants and shirts. She buys a pair of pants for $25 and buys shirts that cost $11 each. What is the

Gala2k [10]

Answer:

3 pairs of shirts and one pair of pants

Step-by-step explanation:

$65-$25(for pants)=$40

$40/$11(how much one shirt cost)=3

7 0

3 years ago