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IceJOKER [234]
3 years ago
11

A-2.5 2a-22.7 a+1.3 21.5 What’s a

Mathematics
1 answer:
rewona [7]3 years ago
8 0

Answer:

2.4

Step-by-step explanation:

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4x+y=15 <br> 3x+5y=41<br> help please!
NemiM [27]

Step-by-step explanation:

x=2. y=7

4(2) + (7) =15

3(2) + 5(7) = 41

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3 years ago
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A person on a lake sees a plane flying overhead. The angle formed by his line of sight to the plane is 39°; If the plane is flyi
Fudgin [204]

⊱─━━━━━━━⊱༻●༺⊰━━━━━━━─⊰

\large \sf \dagger \: {Problem: \dagger}

A person on a lake sees a plane flying overhead. The angle formed by his line of sight to the plane is 39°; If the plane is flying about 5000 ft, find the horizontal ground distance between the person and the plane.

⊱─━━━━━━━⊱༻●༺⊰━━━━━━━─⊰

\large \sf \dagger \: {Solution: \dagger}

  • Let x = horizontal ground distance between the person and the plane.

\qquad\bigstar \: \large \sf{Equation: tan \: 39 \degree = \frac{5000}{x} }

Solving the equation,

\large\qquad \implies\tt{tan \: 39\degree =  \frac{5000}{x}}

\large\qquad \implies \tt{x(tan \: 39 \degree) = \cancel{ x} \large{(} \frac{5000}{ \cancel{x}} \large{)}}

\large\qquad\implies \tt \cancel{ \frac{x \: tan \: 39 \degree}{tan \: 39 \degree}}  =  \frac{5000}{tan \: 39 \degree}

\large\qquad \implies \tt{x =  \frac{5000}{tan \: 39\degree}}

\large \qquad \implies \tt{x  \approx  \pmb{6174.48758}}

Checking the solution,

  • \large\tt{tan \: 39 \degree  =  \frac{5000}{x}}

  • \large \tt{ tan \: 39 \degree =  \frac{5000}{6174.48758}}

  • \large\tt{0.80978 = 0.80978}

<h3>------------------------------</h3>

\large \sf \dagger \: {Answer: \dagger}

  • The horizontal distance between the person and the plane is approximately 6174 ft.

\qquad \rule{200pt}{3pt}

ಠ_ಠ

5 0
2 years ago
A newly hatched channel catfish typically weighs 0.3 grams. During the first 6 weeks of life, its growth is approximately expone
Tanzania [10]
Answer: second option 4.33 g

Explanation:

1) The formula is given: A = C(1+r)ˣ ↔ (I used x instead of t just do to limitations of the math editor. Keep in mind that here x is time in days.

2) r is the rate of increasing given: 10% = 10/100 = 0.1

3) C is the initial weight and A is the final weight after x (or t) days.

4) The equation leads to:

A = 0.3 (1 + 0.1)ˣ = 0.3(1.1)ˣ

x = number of days = 7 × number of weeks = 7 × 4 = 28 days

4)  Compute:

A = (0.3g)(1.1)²⁸

A = 4.33g ← answer
5 0
4 years ago
Which of the ratios below is equivalent to 5:2? Select all that apply.
Nata [24]

Answer:

D

Step-by-step explanation:

This is because they are both mulitplied by two so they are still equivalent

6 0
3 years ago
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