How to change the format of the equation y-5=x

Christopher is deciding between two landscaping companies for his place of business.

Eddi Din [679]

Answer:

A=30t+200

B=50t+100

The number of hours,t, that would make the cost of each company the same is 5.

30(5)+200= A

150+200=350

50(5)+100= B

250+100=350

Step-by-step explanation:

3 0

3 years ago

Which of the following is a solution of x2 + 5x = −2?

adoni [48]

X^2 + 5x = -2
x^2 + 5x + 2 = 0

x = -b (+-) sqrt (b^2 - 4ac) / 2a
a = 1, b = 5, and c = 2

x = -5 (+-) sqrt (5^2 - 4(1)(2)) / 2(1)
x = -5 (+-) sqrt (25 - 8) / 2
x = -5 (+-) sqrt (17) / 2

answer is : negative 5 plus or minus the square root of 17 divided by 2

4 0

3 years ago

Read 2 more answers

Please hurry and answer this question

belka [17]

Answer:

B

12000 divides by 2880 is 42! Hope this could help

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Write an equation that is perpendicular to and 3x+y=3 whose y-intercept 5. Anyone please help me, no link just explain how to do

Liula [17]

Answer:

$y = \frac{1}{3}x + 5$

Step-by-step explanation:

By definition, two lines are perpendicular if and only if their slopes are negative reciprocals of each other: $m = - \frac{1}{m_{2} }$ , or equivalently, $m_{1} * m_{2} = -1$ .

Given our linear equation 3x + y = 3 (or y = -3x + 3):

We can find the equation of the line (with a y-intercept of 5) that is perpendicular to y = -3x + 3 by determining the negative reciprocal of its slope, -3, which is $\frac{1}{3}$ .

To test whether this is correct, we can take first slope, $m_{1} = -3$ , and multiply it with the negative reciprocal slope $m_{2} = \frac{1}{3}$ :

$m_{1} * m_{2} = -1$

$-3 * \frac{1}{3} = -1$

Therefore, we came up with the correct slope for the other line, which is $\frac{1}{3}$ .

Finally, the y-intercept is given by (0, 5). Therefore, the equation of the line that is perpendicular to 3x + y = 3 is:

$y = \frac{1}{3}x + 5$

7 0

2 years ago

let f(x)= p+ 8/x-q. the line x=4 is a vertical asymptote to the graph of f. what is the value of q and p, if the y intercept is

svlad2 [7]

Answer:

The value of q and p is 4 and -24 respectively.

Step-by-step explanation:

Being $f(x)=\frac{p+8}{x-q}$ , the line x=4 is a vertical asymptote to the graph of f(x). The line r is an asymptote of a function if the graph of the function is infinitely close to the line r. That is, an asymptote is a line to which a function approaches indefinitely, without ever touching it.

Being a rational function that which can be expressed as the quotient of two polynomials, a vertical asymptote occurs when the denominator is 0, that is, where the function is not defined. In this case:

x - q= 0

Solving:

x= q

Being the line x=4 the vertical asymptote, then

4=q

Then the function f (x) is:

$f(x)=y=\frac{p+8}{x-4}$

The y intercept is (0,4). This is, x= 0 and y=4. Replacing:

$4=\frac{p+8}{0-4}$

Solving:

$4=\frac{p+8}{-4}$

4*(-4)= p+8

-16= p+8

-16 - 8= p

-24= p

The value of q and p is 4 and -24 respectively.

7 0

3 years ago