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Aleksandr-060686 [28]
3 years ago
11

What is the slope of the line that passes through the points (-6, -8)(−6,−8) and (-14, 4) ?(−14,4)? Write your answer in simples

t form.
Mathematics
1 answer:
creativ13 [48]3 years ago
8 0

Answer:

\huge\boxed{slope=-\dfrac{3}{2}}

Step-by-step explanation:

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have two points (-6, -8) and (-14, 4).

Substitute

x_1=-6,\ y_1=-8,\ x_2=-14,\ y_2=4

m=\dfrac{4-(-8)}{-14-(-6)}=\dfrac{4+8}{-14+6}=\dfrac{12}{-8}=-\dfrac{12:4}{8:2}=-\dfrac{3}{2}

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Arc is 41 and angle is 40. I have no other given information but I have to find x
tiny-mole [99]

First of all I want to point out you drew the diagram a little wrong. The Arc is 41 doesn't mean its 41 degrees it means it has length 41 so remove the degrees symbol.

Now for the answer the other arc have to have angle 40 too because vertical angles. And because the radius is the same, both of the length has formula 40/360*pi*2*radius which is 41 in this case. So x has to be 41 also :) Done!

7 0
3 years ago
When an object moves in a circle the __________ of the object is continually changing. What is the missing word in this sentence
Bezzdna [24]

Answer:

velocity

Step-by-step explanation:

The velocity of the object is continually changing.  This velocity is the slope of the tangent line to the curve at a given point on the curve.

3 0
3 years ago
What is the solution of the system?
Kryger [21]
Greetings!

Solve the System, using Elimination:
\left \{ {{4x+2y=18} \atop {2x+3y=15}} \right.

Multiply Equation #2 by 2:
\left \{ {{4x+2y=18} \atop {2(2x+3y)=2(15)}} \right.

\left \{ {{4x+2y=18} \atop {4x+6y=30}} \right.

Eliminate variable x:
-\frac{ \left \{ {{4x+2y=18} \atop {4x+6y=30}} \right.}{0x-4y=-12}

4y=-12

Divide both sides by 4:
\frac{4y}{4}= \frac{12}{4}

y=3

Input this value into one of the Equations: 
4x+2y=18

4x+2(3)=18

Simplify:
4x+6=18

(4x+6)+(-6)=(18)+(-6)

4x=12

Divide both sides by 4.
\frac{4x}{4}= \frac{12}{4}

x=3

The Solution to this System (The Point of Intersection):
\boxed{(3,3)}

I hope this helped!
-Benjamin
7 0
3 years ago
How do you solve sin (5pi/3) without a calculator?
Savatey [412]

very simple, we use the formula sin(a+b)=sinacosb + sinbcosa and sin(20)=2sinacosa

5pi = 2pi/3+3pi/3,

First, we use sin(a+b)=sinacosb + sinbcosa

sin(5pi/3)=sin(2pi/3+3pi/3)= sin(2pi/3+pi)= sin(2pi/3)cos(pi) +sin(pi)cos(2pi/3)

but we know that sin(pi)= 0, and cos (pi) = -1, so sin(5pi/3)= - sin(2pi/3)

now, use sin(2a)=2sinacosa, sin(5pi/3)= - sin(2pi/3)= -2sin(pi/3)cos(pi/3)

sin<span>(5pi/3)=  -2sin(pi/3)cos(pi/3)</span>

<span>sin(pi/3)= 0.86, cos(pi/3)=0.5, finally we have   </span>sin<span>(5pi/3)=  -0.86 x 0.5= -0.43</span>

5 0
3 years ago
Read 2 more answers
I will mark as brainest
daser333 [38]

subtract 3 from 23 and u will get 20 then divide 2 by 2 and 2 by 20

x= 10

8 0
3 years ago
Read 2 more answers
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