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ASHA 777 [7]
3 years ago
12

Fill in the blank to make the two fractions equivalent. 4/5= ?/25

Mathematics
2 answers:
insens350 [35]3 years ago
7 0

Answer:

20.00

Step-by-step explanation:

barxatty [35]3 years ago
7 0

Answer:

4/5=20/25

Step-by-step explanation:

You might be interested in
Is the set of multiples of 4 closed under addition? Explain why or provide a counterexample if not.
ad-work [718]
The right answer for the question that is being asked and shown above is that: "B. Yes, because the sum of any two multiples of 4 is also a multiple of 8." <span>the set of multiples of 4 closed under addition</span>
4 0
3 years ago
On the main floor of a theatre the number of seats per row increases at a constant rate. Jack counts 31 seats in row 3 and 37 se
Valentin [98]

Answer: 65 seats in row 20

Step-by-step explanation: 3 = 31, 6 = 37 the difference is 3 rows but 6 seats so its going up 2 every row therefor you need 14 rows after row 6 so 14 * 2 + 37 = 65 seats

7 0
4 years ago
The three circles are all centered at the center of the board and are of radii 1, 2, and 3, respectively.Darts landing within th
FromTheMoon [43]

Answer:

a) P=0.262

b) P=0.349

c) P=0.215

d) E(x)=12.217

e) P=0.603

Step-by-step explanation:

The question is incomplete.

Complete question: "The three circles are all centered at the center of the board (square of side 6) and are of radii 1, 2, and 3, respectively.Darts landing within the circle of radius 1 score 30 points, those landing outside this circle, butwithin the circle of radius 2, are worth 20 points, and those landing outside the circle of radius2, but within the circle of radius 3, are worth 10 points. Darts that do not land within the circleof radius 3 do not score any points. Assume that each dart that you throw will land on a point uniformly distributed in the square, find the probabilities of the accompanying events"

(a) You score 20 on a throw of the dart.

(b) You score at least 20 on a throw of a dart.

(c) You score 0 on a throw of a dart.

(d) The expected value on a throw of a dart.

(e) Both of your first two throws score at least 10.

(f) Your total score after two throws is 30.

As the probabilities are uniformly distributed within the area of the board, the probabilities are proportional to the area occupied by the segment.

(a) To score 20 in one throw, the probabilities are

P(x=20)=P(x=20\&30)-P(x=30)=\frac{\pi r_2^2}{L^2} -\frac{\pi r_1^2}{L^2}\\\\P(x=20)=\frac{\pi(r_2^2-r_1^2)}{L^2}=\frac{3.14*(2^2-1^2)}{6^2}=\frac{3.14*3}{36} =0.262

(b) To score at least 20 in one throw, the probabilities are:

P(x\geq 20)=P(x=20\&30)=\frac{\pi r_2^2}{L^2}=\frac{3.14*2^2}{6^2} =0.349

(c) To score 0 in one throw, the probabilities are:

P(x=0)=1-P(x>0)=1-\frac{\pi r_3^2}{L^2} =1-\frac{3.14*3^2}{6^2} =1-0.785=0.215

(d) Expected value

E(x)=P(0)*0+P(10)*10+P(20)*20+P(30)*30\\\\E(x)=0+\frac{\pi(r_3^2-r_2^2)}{L^2}*10+ \frac{\pi(r_2^2-r_1^2)}{L^2}*20+\frac{\pi(r_1^2)}{L^2}*30\\\\E(x)=\pi[\frac{(3^2-2^2)}{6^2}*10+\frac{(2^2-1^2)}{6^2}*20+\frac{1^2}{6^2}*30]\\\\E(x)=\pi[1.389+1.667+0.833]=3.889\pi=12.217

(e) Both of the first throws score at least 10:

P(x_1\geq 10; x_2\geq 10)=P(x\geq 10)^2=(\frac{\pi r_3^2}{L^2} )^2=(\frac{3.14*3^2}{6^2} )^2=0.785^2=0.616

(f) Your total score after two throws is 30.

This can happen as:

1- 1st score: 30, 2nd score: 0.

2- 1st score: 0, 2nd score: 30.

3- 1st score: 10, 2nd score: 20.

4- 1st score: 20, 2nd score: 10.

1 and 2 have the same probability, as do 3 and 4, so we can add them.

P(2x=30)=2*P(x_1=30;x_2=0)+2*P(x_1=20;x_2=10)\\\\P(2x=30)=2*P(x_1=30)P(x_2=0)+2*P(x_1=20)P(x_2=10)\\\\P(2x=30)=2*\frac{\pi r_1^2}{L^2}*(1-\frac{\pi r_3^2}{L^2})+2*\frac{\pi(r_2^2-r_1^2)}{L^2}*\frac{\pi(r_3^2-r_2^2)}{L^2}\\\\P(2x=30)=2*\frac{\pi*1^2}{6^2}*(1-\frac{\pi*3^2}{6^2})+2*\frac{\pi(2^2-1^2)}{6^2}*\frac{\pi(3^2-2^2)}{6^2}\\\\P(2x=30)=2*0.872*0.215+2*0.262*0.436=0.375+0.228=0.603

6 0
3 years ago
how many 1 1/2 centimeter cubes can fit into a rectangular prism that has a length of 12 centimeters , a width of 6 centimeters
VLD [36.1K]

The long, straightforward, brute-force way to slog through the problem:

The prism is 12cm x 6cm x 9cm.

Volume of the prism = (12 x 6 x 9) = 648 cm³

Volume of each little cube = (1.5 x 1.5 x 1.5) = 3/375 cm³

Number of little cubes that fit into the prism =  (648 cm³) / (3.375 cm³) = <em>

                                                                                     192 of them</em>


=============================================

The elegant but almost equally long way to master the problem:

The prism is 12cm x 6cm x 9cm.

If each dimension of your measuring cubie is 1.5cm,
then the prism measures

     (8 cubie lengths) x (4 cubie widths) x (6 cubie heights) .

Its volume is  (8 x 4 x 6) = <em>192 measuring cubies</em>.


8 0
3 years ago
Find the area of the figure.
Slav-nsk [51]

Answer:

132cm

Step-by-step explanation:

Split there firgue into shapes you know

there is a rectangle and a Trapezoid

A = bh

A = 7×4

A = 28cm

Trapezoid

A = 1/2h(b+b)

A = 1/2×8(19+7)

A = 1/2×8(26)

A = 1/2(208)

A = 104cm

Add them together

104 + 28 = 132

4 0
3 years ago
Read 2 more answers
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