Width: 84/3 = 28
Length: 93/3 = 31
There are 28 blocks along the width
There are 31 blocks along the length
Let m and j be the current ages of Matthew and Jenny, respectively.
Now, Matthew is 3 times as old as Jenny, so the variables are in the following relation:
![m=3j](https://tex.z-dn.net/?f=m%3D3j)
In 7 years, both of them will be 7 years older, i.e. their ages will be m+7 and j+7, and Matthew will be twice as old:
![m+7=2(j+7)](https://tex.z-dn.net/?f=m%2B7%3D2%28j%2B7%29)
Now, remembering that m=3j, we can rewrite the second equation as
![3j+7=2j+14 \iff j = 7](https://tex.z-dn.net/?f=3j%2B7%3D2j%2B14%20%5Ciff%20j%20%3D%207)
So, Jenny is 7 and Matthew is 21 (he's 3 times older).
In fact, in 7 years, they will be 14 and 28, and Matthew will be twice as old.
3 kilograms = 4.86
So one kilogram = 4.86/3 = 1.62
2 kilograms = 1.62 × 2 = 3.24
Answer:
$60 x 20% = $12
$60 + $12 = $ 72
Step-by-step explanation:
Note that the measurements of the side of the squares are the same.
Area = base x height
Area = length x width
The area given is 400
Root 400 to get the length of the sides
√400 = 20
20 in. is your side measurement
hope this helps