Select ALL terms that are like terms with 10x3 x3 хЗу 10x 2x3

Mathematics

1 answer:

svet-max [94.6K]3 years ago

3 0

Answer:nbcmbcvd

chmcnbcvvkg

Step-by-step explanation:

nvnggvcmvc,nbchgfhgsfd

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Diring a scuba dive ,lainey descended to apoint 30 feet below the ocean surace.she continued her descent at a rate of 30 feet pe

Phoenix [80]

Is that the entire question?

6 0

3 years ago

A child weighs 44 lbs. The physician orders a medication for 10 mg/Kg/day. What do you give per day? (Use 0.45 for your conversi

Bond [772]

Answer:

198 mg

Step-by-step explanation:

A child weighs 44 lbs.

Step 1

We convert the child's weight to kg

1 Ibs = 0.45kg

44 Ibs = x

Cross Multiply

1 Ibs × x = 44 Ibs × 0.45 kg

x = 44 Ibs × 0.45 kg/1 Ibs

x = 19.8 kg

Step 2

The physician orders a medication for 10 mg/Kg/day.

From the above statement, we know that:

10mg = 1 kg

Hence, what you give per day is calculated as:

1 kg = 10 mg

19.8kg = x

Cross Multiply

1 kg × x = 19.8kg × 10mg

x = 19.8kg × 10mg/1kg

x = 198mg

Therefore, what you will give per day to a child of 19.8kg(44 Ibs) is 198mg per day

3 0

3 years ago

When fritz drives to work his trip takes 40 minutes, but when he takes the train it takes 30 minutes. find the distance fritz t

sweet-ann [11.9K]

Distance = rate*time

convert minutes to hour first because the question talking about 15 mile per hour
40 mins = 40/60 2/3 hrs
30 mins = 30/60 = 1/2hrs

Assume that s be the speed when Fritz driving, so
s + 15 will be the speed of the train.

We know the time we know the speed, Next
distance that Fritz drive = $\frac{2}{3}s$
distance the train travel = $\frac{1}{2}(s+15)$

The question: Assume that the train travels the same distance as the car
==> $\frac{2}{3}s = \frac{1}{2}(s+15)$
==> $\frac{2}{3}s = \frac{1}{2}s + \frac{15}{2}$
==> $\frac{2}{3}s - \frac{1}{2}s = \frac{15}{2}$
==> $\frac{1}{6}s = \frac{15}{2}$
==> $\frac{6}{1} * \frac{1}{6}s = \frac{15}{2} * \frac{6}{1}$
==> $s = 45$
Now we know that Fritz drive at 45 mph,
distance = $\frac{2}{3} * 45 = 30 miles$