Answer:
we're just multiplying X × 2 every time so (y=80)
Area=1/2bh
h=altitude
b=legnth of base
b is 3 times h
b=3h
divide by 3
b/3=h
area=1/2bh
subsitute b/3 for h
54=1/2(b)(b/3)
multiply bothsides by 2/1
108=b(b/3)
108=(b^2)/3
multipy both sides by 3
324=b^2
square root boh sides
18=b
legnth of base=18
Answer:
y = 4 sin(½ x) − 3
Step-by-step explanation:
The function is either sine or cosine:
y = A sin(2π/T x) + C
y = A cos(2π/T x) + C
where A is the amplitude, T is the period, and C is the midline.
The midline is the average of the min and max:
C = (1 + -7) / 2
C = -3
The amplitude is half the difference between the min and max:
A = (1 − -7) / 2
A = 4
The maximum is at x = π, and the minimum is at x = 3π. The difference, 2π, is half the period. So T = 4π.
Plugging in, the options are:
y = 4 sin(½ x) − 3
y = 4 cos(½ x) − 3
Since the maximum is at x = π, this must be a sine wave.
y = 4 sin(½ x) − 3
to get the equation of any straight line we only need two points off of it, hmmm let's use P and Q here and then let's set the equation in standard form, that is
standard form for a linear equation means
• all coefficients must be integers, no fractions
• only the constant on the right-hand-side
• all variables on the left-hand-side, sorted
• "x" must not have a negative coefficient
![(\stackrel{x_1}{6}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{6}}}\implies \cfrac{2}{-3}\implies -\cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{2}{3}}(x-\stackrel{x_1}{6})](https://tex.z-dn.net/?f=%28%5Cstackrel%7Bx_1%7D%7B6%7D~%2C~%5Cstackrel%7By_1%7D%7B0%7D%29%5Cqquad%20%28%5Cstackrel%7Bx_2%7D%7B3%7D~%2C~%5Cstackrel%7By_2%7D%7B2%7D%29%20~%5Chfill%20%5Cstackrel%7Bslope%7D%7Bm%7D%5Cimplies%20%5Ccfrac%7B%5Cstackrel%7Brise%7D%20%7B%5Cstackrel%7By_2%7D%7B2%7D-%5Cstackrel%7By1%7D%7B0%7D%7D%7D%7B%5Cunderset%7Brun%7D%20%7B%5Cunderset%7Bx_2%7D%7B3%7D-%5Cunderset%7Bx_1%7D%7B6%7D%7D%7D%5Cimplies%20%5Ccfrac%7B2%7D%7B-3%7D%5Cimplies%20-%5Ccfrac%7B2%7D%7B3%7D%20%5C%5C%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20%5Ctextit%7Bpoint-slope%20form%7D%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20y-y_1%3Dm%28x-x_1%29%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D%5Cimplies%20y-%5Cstackrel%7By_1%7D%7B0%7D%3D%5Cstackrel%7Bm%7D%7B-%5Ccfrac%7B2%7D%7B3%7D%7D%28x-%5Cstackrel%7Bx_1%7D%7B6%7D%29)
![\stackrel{\textit{multiplying both sides by }\stackrel{LCD}{3}}{3(y-0)~~ = ~~3\left( -\cfrac{2}{3}(x-6) \right)}\implies 3y=-2(x-6) \\\\\\ 3y=-2x+12 \implies \stackrel{a}{2} x+\stackrel{b}{3} y=12](https://tex.z-dn.net/?f=%5Cstackrel%7B%5Ctextit%7Bmultiplying%20both%20sides%20by%20%7D%5Cstackrel%7BLCD%7D%7B3%7D%7D%7B3%28y-0%29~~%20%3D%20~~3%5Cleft%28%20-%5Ccfrac%7B2%7D%7B3%7D%28x-6%29%20%5Cright%29%7D%5Cimplies%203y%3D-2%28x-6%29%20%5C%5C%5C%5C%5C%5C%203y%3D-2x%2B12%20%5Cimplies%20%5Cstackrel%7Ba%7D%7B2%7D%20x%2B%5Cstackrel%7Bb%7D%7B3%7D%20y%3D12)
What do u want me to do?
They are in Fraction form