Answer:
A) (-3, 5)
General Formulas and Concepts:
<u>Algebra I</u>
- Solving systems of equations by graphing
Step-by-step explanation:
The solution set to any systems of equations is where the 2 lines intersect. According to the graph, we see that the 2 lines intersect at (-3, 5). Therefore, our answer is A.
Answer:
65.4
Step-by-step explanation:
60*.09 = 5.4
60+5.4 = 65.4
<span><span><span><span>(<span>15^2</span>)</span><span>(<span>y^2</span>)</span></span>−<span>x^3</span></span>+7</span><span>=<span><span><span><span>225<span>y^2</span></span>+</span>−<span>x^3</span></span>+7</span></span>
<span>=<span><span><span>−<span>x^3</span></span>+<span>225<span>y^2</span></span></span>+<span>7</span></span></span>
In this equation we start by filling in the N with "1" then"2" then "3" and so on
3n+4=
3(1)+4=7
3(2)+4=10
3(3)+4=13
3(4)+4=16
The zeros for this function are -2, -1 and a double root of 0.
You can find this by first factoring the polynomial on the inside of the parenthesis. Polynomials like this can be factored by looking for two numbers that multiply to the constant (2) and add up to the second coefficient (3). The numbers 2 and 1 satisfy both of those needs and thus can be used as the numbers in a factoring.
x^2(x^2 + 3x + 2)
x^2(x + 2)(x + 1)
Now to find the zeros, we set each part equal to 0. You may want to split the x^2 into two separate x's for this purpose.
(x)(x)(x + 2)(x + 1)
x = 0
x = 0
x + 2 = 0
x = -2
x + 1 = 0
x = -1
