Given the radius of 50 miles and the line joining the cities at (0, 56) and (58, 0), the transmitter signal can be picked during 59.24 miles of the drive.
<h3>How can the duration of signal reception be found?</h3>
Radius of broadcast of the transmitter = 50 miles
Location of starting point = 56 miles north of the transmitter
Location of destination city = 58 miles east of the transmitter
Therefore we have;
Slope of the line joining the two cities
= 56 ÷ (-58) = -0.966
Which gives the equation of the line as follows;
y = -0.966•x + 56
The equation of the circle is;


1.933156•x^2 - 108.192•x + 636 = 0
Which gives;
Therefore;
When x = 6.67, we have;
- y = -0.966 × 6.67 + 56 = 49.56
When x = 49.29, we have;
- y = -0.966 × 49.29 + 56 = 8.4
The length of the drive, during which the driver can pick the signal, <em>l</em>, is therefore;
l = √((49.56-8.4)^2 + (49.29-6.67)^2) = <u>59.24 miles</u>
- The length of the drive during which the signal is received is 59.24 miles
Learn more about the equation of a circle here:
brainly.com/question/502872
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Answer:
cos R = .38
Step-by-step explanation:
First you need to find the length of the hypotenuse.
Use a squared + b squared = c squared
100 + 576 = c squared
square root of 676 is 26
CosR is adjacent over hypotenuse.
Adjacent is 10
Hypotenuse is 26
10/26 = .38
Answer:
x= 1/2 and -3/4
Step-by-step explanation:
By using factorization, we can solve this equation.
8x^2+2x-3=0
Factor:
(2x-1)(4x+3)=0
Solve:
2x-1=0
2x=1
x=1/2
Solve again:
4x+3=0
4x=-3
x=-3/4
Hope this helped
The correct answer is
<span>a4b<span>6 I think also your question is missed up next time fix it</span></span>
Answer:
Since you want me to answer 3 lb 1 oz - 1 lb 15 oz instead, the answer is 18 oz
Step-by-step explanation: